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2 years ago

NEED HELP!

1 answer:

8 0

You know from the y-intercept that the equation will have a +y^2/12 term in it. Then for y=6, you have
.. 6^2/12 -x^2/b = 1
.. 2 = x^2/b
.. b = x^2/2
If your point is (2√3, 6), then this is
.. b = (2√3)^2/2 = 12/2 = 6

Then the hyperbola's equation is
.. y^2/12 -x^2/6 = 1 . . . . . . . . selection D

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Step-by-step explanation:

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3 years ago

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2 years ago

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Klio2033 [76]

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1 year ago

G(x) = x3 - 4 h(x) = x2 + 2 Find h(-2) - g(-1)

Lady bird [3.3K]

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

g(x) = x³ - 4

h(x) = x² + 2

h(-2) is x = -2

g(-1) is x = -1

Step 2: Find h(-2) - g(-1)

Substitute: ((-2)² + 2) - ((-1)³ - 4)
Exponents: (4 + 2) - (-1 - 4)
Add/Subtract: 6 - (-5)
Subtract: 11

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2 years ago