Answer:
I think Oad is not ture
Step-by-step explanation:
didnot exactly sorry'
Answer:
200π
Step-by-step explanation:
Graph: desmos.com/calculator/pwa9vqzmpy
The region is inside a horizontal parabola y = (5x)^½, starting at its vertex at x=0 and ending at x=5. Cut a thin vertical slice with thickness dx and position x.
Revolving this thin slice about the y-axis, we get a cylindrical shell with radius x, thickness dx, and height 2y. The volume of the shell is:
dV = 2π (x) (2y) (dx)
dV = 4π xy dx
dV = 4π x (5x)^½ dx
dV = 4π√5 (x^³/₂) dx
The total volume is the sum of all the shell volumes from x=0 to x=5.
V = ∫₀⁵ dV
V = ∫₀⁵ 4π√5 (x^³/₂) dx
Evaluating the integral:
V = 4π√5 ∫₀⁵ (x^³/₂) dx
V = 4π√5 (⅖ x^⁵/₂) |₀⁵
V = 4π√5 [(⅖ 5^⁵/₂) − (⅖ 0^⁵/₂)]
V = 200π
The volume of the solid is 200π cubic units.
Step-by-step explanation:
648/18
18/64=3 remaining 10
bring 8 down making 108
108/18=12
3 and 12=312
ans =312
Area=legnth times width
legnth is 1 less than 2 times width
l=legnth
w=width
l=-1+2w
l=2w-1
area=lw
area=45
subsitute
45=lw
45=(2w-1)w
distribute
45=2w^2-w
subtract 45 from both sides
0=2w^2-w-45
factor because if we have xy=0 and we factor we can assume that x and/or y=0 so
trial and error factor
0=(2w+9)(w-5)
set each to zero
0=2w+9
subtract 9
-9=2w
divide 2
-4.5=w
impossible since width cannot be negative so discard
w-5=0
add 5 to both sides
w=5
true
subsitute
l=2w-1
l=2(5)-1
l=10-1
l=9
w=5 cm
l=9 cm
Y=3-x has a negative slope