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Advocard [28]
3 years ago
5

What are two ways you can represent the number 27 using the number 3?

Mathematics
2 answers:
vivado [14]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

27 = 3 × 9 ← is one way

27 = 3³ ← is another way

raketka [301]3 years ago
7 0
Here are some other ways of representing the number 17 using the number 3

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$160 divided 5g unit rate
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The answer is 32$ per gram. You just divide 160 by 5 to get the answer. 

Hope that helps!!!

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4 years ago
50 ptssss <br> what is 2+2
yKpoI14uk [10]

Answer:

4!!!

Step-by-step explanation:

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4 0
3 years ago
Which of the following numbers is divisible by 3, 5, and 10?
Alex787 [66]

Answer:

D. 30

Step-by-step explanation:

A. 15

3 and 5 are liable. 10 is not

B. 20

5 and 10 liable. 3 is not.

C. 25

5 is liable. 3 and 10 is not.

D. 30

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8 0
3 years ago
Read 2 more answers
Enter a digit in each box to complete the division problem.
FromTheMoon [43]

Step-by-step explanation:

2527 is the first line so 5 in the box

then 47 so a 4 in that box

top answer row

315 E7 so a 5 in that box.

8 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
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