Step-by-step explanation:
There are 40 DuBois students going on a field trip.
Each one pays their teacher $8.75 to cover admission to the museum and lunch.
Admission for the students is $120 and each one gets an equal amount to spend on lunch.
To Find :
How much will each DuBois student be able to spend on lunch.
Solution :
Amount they paid for admission :
\begin{gathered}P =\$ \dfrac{120}{40}\\\\P=\$3\end{gathered}P=$40120P=$3
Now, amount of money to spend on lunch is 8.75 -8.75−3 = $5.75 .
Hence, this is the required solution.
Answer:
(4;0)
Step-by-step explanation:
y=0
2x-3×0=8
2x=8
x=4
Answer:
0 2
1 4 ⟌ 3 7
- 0
3 7
- 2 8
9
2 r 9
for 37 divided by 14
0 7
1 3 ⟌ 9 6
- 0
9 6
- 9 1
5
7 r 5
for 96 divided by 13
0 2 0
4 1 ⟌ 8 5 8
- 0
8 5
- 8 2
3 8
- 0
3 8
for 858 divided by 41
20 r 38
Step-by-step explanation:
Let us denote the number of tiles by

.
In the first store, if Darin bought

tiles, he would need to spend:

(measured in $)
In the second store, if Darin bought

tiles, he would need to spend:

(measured in $)
For the cost to be the same at both stores, it means (measured in $)

Moving

over to the left hand side and changing signs:

tiles
Let's check. If he buys 60 tiles in the first store, he spends:
$0.79×60 + $24 = $47.40 + $24 = $71.40
If he buys 60 tiles in the second store, he spends:
$1.19×60 = $71.40
∴
Darin needs to buy 60 tiles for the cost to be the same at both stores.