V:W
1:7
1+7=8
1/8*45=5.625 ml of vinegar
The given values are:
p = 22% = 0.22
Zc = 1.645 at 90% confidence level.
margin of error, E = 0.04
The formula we can use here is:
E = sqrt(pq/n) * Zc
0.04 = sqrt(0.22*(1-0.22)/n)*1.645
n = (0.22*(1-0.22))*(1.645/0.04)^2
n = 290.22
hence minimum sample size = 290
Too blury,take a good pic
Answer:
Therefore the population will be maximum when x=30 inches.
Step-by-step explanation:
Given that, the mosquito population is a function of rainfall and can be approximated by the formula

where x is the number of inches of rainfall.

Differentiating with respect to x

Again differentiating with respect to x

Now we set N'(x)=0





Since at x=30, N''(x)<0, So at x=30, N(x) has maximum value.
Therefore the population will be maximum when x=30 inches.
Answer:
x=15
Step-by-step explanation:
Step 1: Multiply both sides by 2.
Step 2: Simplify both sides of the equation.
6x+18=108
Step 3: Subtract 18 from both sides.
6x+18−18=108−18
6x=90
Step 4: Divide both sides by 6.
x=15