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Likurg_2 [28]
3 years ago
6

What is 0.0000234 in scientific notation

Mathematics
1 answer:
Anni [7]3 years ago
6 0

Answer:

0.0000234 to standard form

2.34 x 10^ -5

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What would be the result of 100 plus 4% for 12 years
VashaNatasha [74]

Answer:

100.04

Step-by-step explanation:

8 0
3 years ago
At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
MAXImum [283]

<u>Answer-</u>

At x= \frac{1}{2304e^4-16e^2} the curve has maximum curvature.

<u>Solution-</u>

The formula for curvature =

K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}

Here,

y=4e^{x}

Then,

{y}' = 4e^{x} \ and \ {y}''=4e^{x}

Putting the values,

K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

 {k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}

Now, equating this to 0

(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0

\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})

\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})

\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}

\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}

\Rightarrow 2304e^{2x}-16e^{2x}-1=0

Solving this eq,

we get x= \frac{1}{2304e^4-16e^2}

∴ At  x= \frac{1}{2304e^4-16e^2} the curvature is maximum.




6 0
3 years ago
2. What is 9 squared. <br> a. 3<br> b. 81<br> C. 18<br> O d. 11
vitfil [10]

Answer:

81

Step-by-step explanation:

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2 years ago
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Are the 2 triangles congruent? If so, what postulate did you use?
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Answer:

Step-by-step explanation:

4

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Which of the statements is true regarding the graphed functions ?
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F(x) means the function defined at that x value. It really just means what y value when x is equal to that input. So we can see clearly that A is false. They’re nearly opposite y values. B is also obviously false since the y values aren’t equal. C is the same case, the y values aren’t equal. D is true. When x = -2 for both functions, we can see the y value is the same. They also intercept, so that’s a pretty dead giveaway

D.)
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3 years ago
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