Answer:
Step-by-step explanation:
<u>Given</u>
- ΔABC ⇒ A(- 1, 3), B(- 1, 1), C(3, 1)
- ΔA'B'C' ⇒ A'(2, - 2), B'(2, - 4), C'(6, - 4)
<u>Comparing the coordinates of the corresponding vertices, we see the difference:</u>
It means the ΔABC has been translated 3 units right and 5 units down
Correct answer choices are B and E
Answer:
6 6/8 OR 6 3/4
Step-by-step explanation:
2 5/8 +4 1/8
6 6/8
SImplify= 6 3/4
Here we will explain how to calculate two thirds of 864.
Two thirds of 864 is simply two thirds times 864, which can be written as follows:
Two/thirds x 864
Furthermore, you can convert "two" to "2" and "thirds" to "3" and then the equation and answer is:
2/3 x 864 = 576.00
Two thirds written as a fraction is 2/3. You can also write it as a decimal by simply dividing 2 by 3 which is 0.67.<span>If you multiply 0.67 with 864 you will see that you will end up with the same answer as above. </span>
<span>You may also find it useful to know that if you multiply 0.67 with 100 you get 66.67. Which means that our answer of 576.00 is 66.67 percent of 864. </span>
Answer:
5 students are left out in the arrangement.
Step-by-step explanation:
If the number of rows = the number of columns
Then there must be an equal arrangement
Since the total number of students in the school is 2121
Then, the students that are left out in this arrangement = 2121 - (√2121 X √2121
Note the result of the square root would only consider the whole number, the digits after the decimal point signifies the remaining number that can't fit into the arrangement
so, √2121 = 46.05 (so 46 would be used)
= 2121 - (46 X 46)
= 2121 - 2116 = 5
Therefore 5 students are left out in the arrangement.
Answer:
(c) III
Step-by-step explanation:
If you simplify the equations and the left side is identical to the right side, then there are an infinite number of solutions: the equation is true for all values of x.
Another way to simplify the equation is to subtract the right side from both sides. If that simplifies to 0 = 0, then there are an infinite number of solutions.
__
<h3>I. </h3>
2x -6 -6x = 2 -4x . . . . eliminate parentheses
-4x -6 = -4x +2 . . . . no solutions (no value of x makes this true)
__
<h3>II.</h3>
x +2 = 15x +10 +2x . . . . eliminate parentheses
x +2 = 17x +10 . . . . one solution (x=-1/2)
__
<h3>III.</h3>
4 +6x = 6x +4 . . . . eliminate parentheses
6x +4 = 6x +4 . . . . infinite solutions
__
<h3>IV.</h3>
6x +24 = 2x -4 . . . . eliminate parentheses; one solution (x=-7)
