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ladessa [460]
4 years ago
9

Pls pls pls pls pls help me with this :)

Mathematics
1 answer:
torisob [31]4 years ago
4 0

Answer:

Function, not one-to-one

Step-by-step explanation:

The orange numbers don’t have two numbers that are the same, and number 3 has two arrows pointing out of it.

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Write the converse of this statement.if two angles are both obtuse, the two angles are equal.
Aliun [14]

To form the <u>converse</u> of the <u>conditional statement</u>, interchange the <u>hypothesis</u> and the <u>conclusion</u>.

Given conditional statement: "if two angles are both obtuse, the two angles are equal".

Here,

  • hypotesis is:  two angles are both obtuse,
  • conclusion is:  two angles are equal.

Then the converse statement will be: "If two angles are equal, then two angles are both obtuse".

8 0
4 years ago
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Are the triangles congruent if they are which theorem and why?
leonid [27]
Yes the sides are equal to each other
7 0
3 years ago
Help plzz <br> 2decimal places<br> 165 x 0.38²
allsm [11]

Answer:

23.83

Step-by-step explanation:

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3 years ago
If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?
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5/11 = 18/y
5 y = 18 · 11
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y = 198 : 5 
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3 0
3 years ago
If you want to be 95​% confident of estimating the population mean to within a sampling error of plus or minus3 and the standard
Aleksandr [31]

Answer:

The sample size required is at least 171

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

What sample size is​ required?

A samle size of at least n is required, in which n is found when M = 3, \sigma = 20

So

M = z*\frac{\sigma}{\sqrt{n}}

3 = 1.96*\frac{20}{\sqrt{n}}

3\sqrt{n} = 20*1.96

\sqrt{n} = \frac{20*1.96}{3}

(\sqrt{n})^{2} = (\frac{20*1.96}{3})^{2}

n = 170.7

Rouding up

The sample size required is at least 171

5 0
3 years ago
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