If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?
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Answer:
The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>
Step-by-step explanation:
Given:
Initial speed of debris is,
The height 'h' of the debris above the ground is given as:
As per question, . Therefore,
Rewriting the above equation into a standard quadratic equation and solving for 't', we get:
Using quadratic formula to solve for 't', we get:
Therefore, the debris will reach a height of 56 ft twice.
When time during the upward journey, the debris is at height of 56 ft.
Again after reaching maximum height, the debris falls back and at , the height is 56 ft.
Reflecting the polygon FGHI across the line involves flipping the line across the line y = -1
<h3>How to reflect the polygon?</h3>The coordinates are given as:
F(2, – 1), G(5,2), H(8, 3), and I(6, 0)
The line of reflection is given as:
y = -1
To reflect the line, we apply the following rule of reflection
(x,y) (x,-y-2)
So, we have the following coordinates of the image
F' = (2, – 1)
G' = (5,-4)
H' = (8, -5)
I' = (6, -2)
See attachment for the image of the reflected polygon
Read more about reflection at:
