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Pepsi [2]
3 years ago
14

Father is 20 years older than son. if the sum of their ages is 40 years find their age​

Mathematics
2 answers:
Naily [24]3 years ago
5 0

Answer:

Step-by-step explanation:

let the age of son be x

x+x+20=40

2x=40-20

x=20/2

x=10

since age of a father is 20 more than his son's so,

x+20=father's age

10+20

30

therefore fathers age is thirty years and son age is 10 years

sweet-ann [11.9K]3 years ago
4 0

Answer:

20 is the father's 20 is the son

Step-by-step explanation:

20+20=40

40/2=20

40-20=20

another way:

20:n= 40

40-20=20

20:20=40

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In a certain urban are, the relationship between , number of students ,x, in thousands, and the number schools, y, has an x-inte
chubhunter [2.5K]

Answer:

-12 = 3x - 4y

Step-by-step explanation:

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Using the point slope form, we get:

y - 3 = (3/4)(x - 0), or

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6 0
3 years ago
4^2-6(2^x)-16=0<br><br><br>solve for x
ahrayia [7]
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</span><span>-6(2^x) + 4^2 - 16=0

Are you sure it's not   </span>6(2^x) + 4^2 - 16=0  ?

If   6(2^x) + 4^2 - 16=0    is correct, then

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8 0
3 years ago
A culture started with 5000 bacteria after 5 hours it grew to 6500 bacteria predict how many bacteria will be present after 16 h
postnew [5]

Answer:

After 16 hours bacterial count will be 11600.

Step-by-step explanation:

Bacterial growth is always an exponential growth in a given culture.So the formula for the growth will be

Final counts of bacteria = Initial counts × (rate of growth)^{time}

Given from first part Initial counts = 5000

Final counts= 6500 and time of growth = 5 hours

Then we will get the value of rate of growth of bacteria from the bacteria

⇒ 6500 = 5000×(rate)^{5}

(rate)^{5}= \frac{6500}{5000} = 1.3

Rate = \sqrt[5]{1.3} = 1.05

Now again to get the value of bacteria after 16 hours

Final Count = 5000×(1.05)^{16}

                   = 5000×2.32

                   = 11600


7 0
3 years ago
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