Answer:
Option A
|-6 -2|
|1 1|
Step-by-step explanation:
This is a product of a matrix.
So for the first number on the first row, we have;
(4 × -3) - (3 × -2) = -12 + 6 = -6
For the second number on the first row, we have;
(4 × 1) - (3 × 2) = 4 - 6 = -2
For the first number on the second row, we have;
(-1 × -3) - (-1 ×-2) = 3 - 2 = 1
For the second number on the second row, we have;
(-1 × 1) - (-1 × 2) = -1 + 2 = 1
Thus, we now have;
|-6 -2|
|1 1|
The correct way to solve this equation would be:
7=5+3(x-4)
Distribute the Brackets.
3*x=3x
3*4=12
7=5+3x-12
Add like terms.
7=-7+3x
Add 7 to both sides.
(7)+7=(-7+3x)+7
14=3x
Divide both sides by 3.
(14)/3=(3x)/3
4.6667 or 14/3 =x
Both answers are incorrect.
Some the significant mistakes:
-Didn't follow BEDMAS
-How did 7=8(x-4) turn into 78=x-4?
Hope this helps.
-Benjamin
-7+1=6x. -6=6x. So the answer will be -1 bc they have opposite signs
<h2>Solving Equations with Absolute Expressions</h2><h3>
Answer:</h3>
<u>No Solutions</u>
<h3>
Step-by-step explanation:</h3>
Given:

Rewriting the given equation:

We have to realize that the right side of the equation,
, will always be positive no matter what real values of
(because we're taking the absolute value of the expression) and we are equating it to a <em>negative</em> constant number,
. Something that is always positive will never be negative so there's no value for
that satisfies the solution.

<em>You</em><em> </em><em>may</em><em> </em><em>not</em><em> </em><em>read</em><em> </em><em>the</em><em> </em><em>following</em><em> passage</em><em> </em><em>that</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>written.</em>

Solving by positive of the expression:

Solving by the negative of the expression:

Checking: 

is an extraneous solution.
Checking: 

is an extraneous solution.
Since the topic is similar right triangles you need to think of the Pythagorean triples, for this problem use the 3-4-5 triplet ratio