Ask question

Ask question

All categories

2 years ago

8

Find the value of the expression if x=-7

1 answer:

LUCKY_DIMON [66]2 years ago

5 0

Answer: -16

Step-by-step explanation:

49 would be the result of -7 squared. Due to the fact it is negative, it would cancel out to be positive.

For the numerator, 49-1 is equivalent to 48.

48/x+4

-7+4 = -3

48/-3

= -16

You might be interested in

Hope you can read those plz help me

erastova [34]

You use the equation given to solve the problem.

x= 4x9
X=36
The four is for the amount of people. The nine is the cost.

For the questions where you have to find out how much each person paid you would have to divided the amount by the number of people.

So, 36/9= 4.30

Therefore each person paid $4.30.

(Hope this helps you)

4 0

3 years ago

Skylar needs $56 to buy a new video game. If he doubles the amount of money he has now, he will have enough to buy the game with

Semenov [28]

Skylar have 66 Dollars left

7 0

3 years ago

A deal is a deal, so here is a good one, let's see who gets it right. I had $10.00. My mom gives me $30.00, My dad gave me $30.0

Yanka [14]

Answer:

$180 in total!

Step-by-step explanation:

10 + 30 + 30 + 100 + 10 = 180

the uncle and aunt gave their money together, it didn't specify that they each gave 100

6 0

3 years ago

Need help asappppppp

PilotLPTM [1.2K]

Given:

The right triangular prism.

Height of prism = 28 in.

Hypotenuse of base = 25 in.

leg of base = 24 in.

To find:

The lateral surface area of the prism.

Solution:

Pythagoras theorem:

$Hypotenuse^2=Perpendicular^2+Base^2$

Using Pythagoras theorem in the base triangle, we get

$25^2=24^2+Base^2$

$625-576=Base^2$

$\sqrt{49}=Base$

$7=Base$

The perimeter of the triangular base is:

$P=7+25+24$

$P=56$

Lateral area of a triangular prism is:

$A=Ph$

Where, P is the perimeter of the triangular base and h is the height of the prism.

Putting $P=56,h=28$ in the above formula, we get

$A=56(28)$

$A=1568$

Therefore, the lateral area of the prism is 1568 in².

8 0

2 years ago

Sadiq measured the dimensions of a 1 kg bag of sugar and found the length was 9.2 cm, the width was 6 cm and the height was 14.1

garik1379 [7]

Answer:

$d=1.28\times 10^{-6}\ g/cm^3$

Step-by-step explanation:

The mass of a bag of sugar, m = 1 kg = 0.001 g

Length of bag, l = 9.2 cm

Width of bag, b = 6 cm

Height of the bag, h = 14.1 cm

We need to find the density of the sugar bag.

Density = mass/volume

So,

$d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3$

So, the density of the bag is $1.28\times 10^{-6}\ g/cm^3$ .

7 0

2 years ago