Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Group 1:
μ1 = 59.7
s1 = 2.8
n1 = sample size = 12
Group 2:
μ2 = 64.7
s2 = 8.3
n2 = sample size = 15
α = 0.1
Assume normal distribution and equ sample variance
A.)
Null and alternative hypothesis
Null : μ1 = μ2
Alternative : μ1 < μ2
B.)
USing the t test
Test statistic :
t = (m1 - m2) / S(√1/n1 + 1/n2)
S = √(((n1 - 1)s²1 + (n2 - 1)s²2) / (n1 + n2 - 2))
S = √(((12 - 1)2.8^2 + (15 - 1)8.3^2) / (12 + 15 - 2))
S = 6.4829005
t = (59.7 - 64.7) / 6.4829005(√1/12 + 1/15)
t = - 5 / 2.5108165
tstat = −1.991384
Decision rule :
If tstat < - tα, (n1+n2-2) ; reject the Null
tstat < t0.1,25
From t table :
-t0.1, 25 = - 1.3163
tstat = - 1.9913
-1.9913 < - 1.3163 ; Hence reject the Null
Answer: x=- 8 or x=2
Step-by-step explanation:
1. To solve this problem you can applly the quadratic formula, which is shown below:
2. The quadratic equation is:
3. Then:
a=1
b=6
c=-16
4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:
Answer:
Two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle. Which congruence theorem can be used to prove that the triangles are congruent? Two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle.
Answer:
Amount = Initial value × (1 + rate of interest)^years and 374
Step-by-step explanation:
The formula to determine the student population and the estimated student population is given below:
As we know that
Amount = Initial value × (1 + rate of interest)^years
= 284 × (1 + 0.04)^7
= 284 × 1.04^7
= 373.72
= 374
Since z is the midpoint, rz and zt must be equal
4x - 15 = 25
4x = 40
X = 10
Plug the answer in and rz equals 40-15 which is 25.
25 + 25 = 50
Or if you really wanted, since you know 25 is half, just add them together right off the bat. (25 and 25, I mean)
