Ask question

Ask question

All categories

3 years ago

5

Patrick has $5 saved he will save an additional $1 each week which expression represents the amount of money Patrick will have s

aved after W weeks

1 answer:

Rainbow [258]3 years ago

8 0

Answer:

5+1w

Step-by-step explanation:

You might be interested in

Deborah hikes due south for 3 miles. She then turns due west and hikes 4 miles. What is the shortest distance between the starti

Cerrena [4.2K]

Answer:

5 miles

Step-by-step explanation:

The two legs of Deborah's hike form the right-angle legs of a right triangle. The shortest distance is then the hypotenuse of that triangle, found using the Pythagorean theorem.

d^2 = 3^2 + 4^2 = 9 +16 = 25

d = √25 = 5

Deborah ends 5 miles from her start.

8 0

3 years ago

WhichGiven that f(x) = x² + 5x, evaluate f(-2). of the following is equal to ?

Andrew [12]

F(x)= x²+5x
f(x)= -2²+5(-2)
f(x)= 4-10
f(x)= -6
I hope I helped you :)

4 0

3 years ago

Don put $3,000 in a savings account with an interest rate of 5% for three years. If the interest is compounded annually, how muc

nikklg [1K]

Compounded anually means
if you put x in at y percent then
you calculate like this
if you put in x at y percent then the money you earn is
x +(x times y)=z=first year
second year=z+(z times y)=s
third year=s+(s times y)=t

percent means parts out of 100 so 5%=5/100=0.05
'of' can be translated as multiply
so

3000 +(3000 times 0.05)=3150=fisrt year
3150+(3150 times 0.05)=3307.5=second year
3307.5 +(3307.5 times 0.05)=3472.88=tird year

he will have 3472.88 at end of 3 years

3 0

3 years ago

What is 3/38 x 4/13 ?

Aliun [14]

Answer:

B

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

On the planet of Mercury, 4-year-olds average 3 hours a day unsupervised. Most of the unsupervised children live in rural areas,

erastova [34]

Answer:

a

The distribution of X is normal

b

$P(X < 1.4) = 0.12654$

c

$P(X > 3.5) = 0.36051$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 3 \ hours$

The standard deviation is $\sigma = 1.4 \ hours$

Generally given from the question that the amount of time spent alone by the population size is normally distributed then then the distribution of X (i.e the amount of time spent by the sample size (the one Mercurian)) will be normally distributed

Generally the probability that the child spend less than one hour in a day is mathematically represented as

$P(X < 1.4) = P(\frac{X - \mu}{\sigma} < \frac{1.4 - \mu}{\sigma} )$

Here $\frac{X - \mu}{\sigma } = Z (The\ standardized\ value\ of\ X)$

So

$P(X < 1.4) = P(Z < \frac{1.4 - 3.0}{1.4} )$

$P(X < 1.4) = P(Z < -1.1429 )$

From the z-table the value of

$P(Z < -1.1429 )=0.12654$

So $P(X < 1.4) = 0.12654$

Generally the percentage of children that spends over 3.5 hours unsupervised is mathematically represented as

$P(X > 3.5) = P(\frac{X - \mu}{\sigma} > \frac{3.5 - \mu}{\sigma} )$

$P(X > 3.5) = P(Z > \frac{3.5 - 3.0}{1.4} )$

$P(X > 3.5) = P(Z > 0.3571 )$

From the z-table the value of

$P(Z >0.3571 )=0.36051$

So $P(X > 3.5) = 0.36051$

5 0

3 years ago