3000+200+60+4 I think would be the answer from what I remember
Answer:
20 units
Step-by-step explanation:
Let the length be x. According to the question,
- Length = x
- Width = 15% of the length
➝ Width = 15% of the length
➝ Width = 15/100x
➝ Width = 3/20x
We have the perimeter of the rectangle that is 46 units.
![\longrightarrow \sf {Perimeter_{(Rec.)} = 2(L + W) } \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7BPerimeter_%7B%28Rec.%29%7D%20%3D%202%28L%20%2B%20W%29%20%7D%20%5C%5C%20)
![\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7B46%3D%202%5CBigg%20%5Clgroup%20x%20%2B%20%5Cdfrac%7B3%7D%7B20%7Dx%20%5CBigg%20%5Crgroup%20%7D%20%5C%5C%20)
![\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7B46%3D%202%5CBigg%20%5Clgroup%20x%20%2B%20%5Cdfrac%7B3%7D%7B20%7Dx%20%5CBigg%20%5Crgroup%20%7D%20%5C%5C%20)
![\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{20x + 3x}{20} \Bigg \rgroup } \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7B46%3D%202%5CBigg%20%5Clgroup%20%5Cdfrac%7B20x%20%2B%203x%7D%7B20%7D%20%5CBigg%20%5Crgroup%20%7D%20%5C%5C%20)
![\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{23x}{20} \Bigg \rgroup } \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7B46%3D%202%5CBigg%20%5Clgroup%20%5Cdfrac%7B23x%7D%7B20%7D%20%5CBigg%20%5Crgroup%20%7D%20%5C%5C%20)
![\longrightarrow \sf {\dfrac{46}{2}= \dfrac{23x}{20}} \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7B%5Cdfrac%7B46%7D%7B2%7D%3D%20%20%5Cdfrac%7B23x%7D%7B20%7D%7D%20%5C%5C%20)
![\longrightarrow \sf {23= \dfrac{23x}{20}} \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7B23%3D%20%20%5Cdfrac%7B23x%7D%7B20%7D%7D%20%5C%5C%20)
![\longrightarrow \sf {23 \times 20 = 23x} \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7B23%20%5Ctimes%2020%20%3D%2023x%7D%20%5C%5C%20)
![\longrightarrow \sf {460= 23x} \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7B460%3D%2023x%7D%20%5C%5C%20)
![\longrightarrow \sf {\cancel{\dfrac{460}{23}} = x} \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%20%7B%5Ccancel%7B%5Cdfrac%7B460%7D%7B23%7D%7D%20%3D%20x%7D%20%5C%5C%20)
![\longrightarrow \underline{\boxed{ \bf {20\; units = x}}} \\](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Cunderline%7B%5Cboxed%7B%20%5Cbf%20%7B20%5C%3B%20units%20%3D%20x%7D%7D%7D%20%5C%5C%20)
<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>rectang</u><u>le</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u> </u><u>units</u><u>.</u>
Answer:
86
Step-by-step explanation:
Since something minus a negative is just adding, we get 37-(-8)=37+8 or 45. We can do the same with 11-(-30) which is 11+30 or 41. So 45+41=86
Answer:
well 0
Step-by-step explanation:
basically when a point lies on an axis,one of its coordinates must be zero,let's say point a-
if you look at how far the point is from the origin along the x-axis,the answer is zero,therefore the x-coordinate is zero,any point that lies on the y-axis has an x-coordinate of zero.