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Liula [17]
3 years ago
13

WhichGiven that f(x) = x² + 5x, evaluate f(-2). of the following is equal to ?

Mathematics
1 answer:
Andrew [12]3 years ago
4 0
F(x)= x²+5x
f(x)= -2²+5(-2)
f(x)= 4-10
f(x)= -6
I hope I helped you :)
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Element X is a radioactive isotope such that every 66 years, its mass
LenKa [72]

Answer:

194.5315427 grams

Step-by-step explanation:

The half-life of element x would be 66 years. So, after 20 years you would have:

.5^(20/66) x 240=0.810548 x 240

        =194.5315427 grams of the element left ......

3 0
3 years ago
Please help and explain the question is in the picture
Digiron [165]

Answer: 123 square feet

Step-by-step explanation: The question is a little odd, but I can break it down easily. It wants us to find the area of a three foot border around his room.

First, the whole area of his room is 20 x 24 = 480

Next, we have to make the measurements 3 feet smaller on each wall, so 17 x 21 = 357

Finally, to find the area of the border, we simply do 480 - 357 = 123

He needs to buy 123 square feet of carpeting

Hope this helps!

8 0
3 years ago
Read 2 more answers
What is 11 trillion 950 billion 500 million in scientific notation
tensa zangetsu [6.8K]
In order they are

1.1 * 10^12, 9.5 * 10^11 and 5*10^8
4 0
3 years ago
Spencer wrote the following paragraph proof showing that rectangles are parallelograms with congruent diagonals. Quadrilateral R
Komok [63]

We have to prove that rectangles are parallelograms with congruent Diagonals.

Solution:

1. ∠R=∠E=∠C=∠T=90°

2. ER= CT, EC ║RT

3.  Diagonals E T and C R are drawn.

4. Shows Quadrilateral R E CT is a Rectangle.→→[Because if in a Quadrilateral One pair of Opposite sides are equal and parallel and each of the interior angle is right angle than it is a Rectangle.]

5.  Quadrilateral RECT is a Parallelogram.→→[If in a Quadrilateral one pair of opposite sides are equal and parallel then it is a Parallelogram]

6. In Δ ERT and Δ CTR

(a) ER= CT→→[Opposite sides of parallelogram]

(b) ∠R + ∠T= 90° + 90°=180°→→→Because RECT is a rectangle, so ∠R=∠T=90°]

(c) Side TR is Common.

So, Δ ERT ≅ Δ CTR→→[SAS]

Diagonal ET= Diagonal CR →→→[CPCTC]

In step 6, while proving Δ E RT ≅ Δ CTR, we have used

(b) ∠R + ∠T= 90° + 90°=180°→→→Because RECT is a rectangle, so ∠R=∠T=90°]

Here we have used ,Option (D) : Same-Side Interior Angles Theorem, which states that Sum of interior angles on same side of Transversal is supplementary.

6 0
3 years ago
Read 2 more answers
Please Help me!!!
drek231 [11]

Step-by-step explanation:

The displacement of a particle d (in km) as a function of time t (in hours) is given by :

d=2t^3+5t^2-3

Displacement at t = 4 hours,

d(4)=2(4)^3+5(4)^2-3=205\ km

Velocity of particle is given by :

v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t

Velocity at t = 4 hours,

v=6(4)^2+10(4)=136\ km/h

Acceleration of the particle is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10

At t = 4 hours,

a=12(4)+10=58\ km/h^2

Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.

7 0
3 years ago
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