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Liula [17]
3 years ago
13

WhichGiven that f(x) = x² + 5x, evaluate f(-2). of the following is equal to ?

Mathematics
1 answer:
Andrew [12]3 years ago
4 0
F(x)= x²+5x
f(x)= -2²+5(-2)
f(x)= 4-10
f(x)= -6
I hope I helped you :)
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In your own words, explain why there is no solution to the following equation:| x-6|= -8 Also, knowing this, how does it help to
solniwko [45]

Answer:

Step-by-step explanation:

So the two lines before and after the expression means absolute value, or modulus of, knowing this, it means that the answer must always yield positive. So if x-6 is positive, it will stay positive, if x-6 is negative, it will turn positive, therefore it can never yield a negative value.

Now im assuming the second question is meant to be absolute value of x-5 is less than 0, because it makes no sense otherwise.

So now knowing that x-5 is always positive, or 0, but this inequality only wants less than 0, this means there are no solutions for the inequality.

5 0
3 years ago
Could someone please help me
BartSMP [9]

Answer:

x=16°

y=25°

Step-by-step explanation:

7x=112

x=112/7

x=16

90+y=115

y=115-90

y=25

8 0
3 years ago
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Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime
Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0
2 years ago
Is this table a function? why or why not?
gavmur [86]
No because each time it goes up by (1) and in the last one it goes up (2 times) and then decreases (4 times) on the right.
6 0
3 years ago
Factorization (3r^2-9r)(r+3)=0
melomori [17]

Answer:

r=-3, 3,0

factor -

3r(r-3) (r+3) ,

solution-

3r=0 , r=0

3r^2-9r =0

3r^2=9r

r=3,

r+3=0

r= -3

5 0
2 years ago
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