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butalik [34]
3 years ago
11

Please help me with this question I will give you 66 points​

Mathematics
1 answer:
Leokris [45]3 years ago
7 0

Answer:

What is the question?

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What is the following product in simplified form?
erastova [34]

Answer:

a

Step-by-step explanation:

because I just think its a

6 0
3 years ago
The volume of a cylindrical soup can is represented by the expression πr3 + 7πr2, where r is the radius of the cylinder. Which s
Ganezh [65]

Answer:

Step-by-step explanation:

Given the volume of the cylindrical soup expressed as V = πr³+ 7πr²

From V = πr³ + 7πr²;

factor out the common variable

V = πr³ + 7πr²

V = πr²(r+7) ... 1

The original volume of a cylinder V =  πr²h .... 2 where;

r is the radius of the cylinder

h is the height of the cylinder

Equating equation 1 and 2, we will have;

πr²(r+7)  =  πr²h

Divide both sides by  πr²

πr²(r+7)/ πr² = πr²h/ πr²

r+7 = h

h = r+7

<em>Hence the factor in the context given is equivalent to the height of the cylinder written as a function of its radius r</em>.<em> The statement means that the height of the cylindrical soup is 7 more than its radius.</em>

<em></em>

5 0
3 years ago
Four runners are training for long races. Noah Ran 5.123 miles. Andre ran 6.34 miles. Jada ran 7.1 miles. Diego ran 8 miles.
VashaNatasha [74]
5.5 is a lot closer then the others
7 0
3 years ago
Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π ​ )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac
uranmaximum [27]

One way to do this is to notice

\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4

Then

\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}

We have

\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

and since \tan x has a period of \pi,

\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1

and so

\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3

7 0
3 years ago
Determine whether the vectors u and v are parallel, orthogonal, or neither. u = (5,4) v = (-10,9)
12345 [234]

Answer:

Neither

Step-by-step explanation:

5 x -10 = -50

4 x 9 = 36

-50 + 36 = -14 and therefore can not be orthogonal

sqrt(25+16)=sqrt(41)

sqrt(100+81)=sqrt(181)

sqrt(41) x sqrt(181) is not equal to -14 so therefore it is not parallel

So the answer is then neither

6 0
3 years ago
Read 2 more answers
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