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butalik [34]
3 years ago
11

Please help me with this question I will give you 66 points​

Mathematics
1 answer:
Leokris [45]3 years ago
7 0

Answer:

What is the question?

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Answer:

CE = 10.

Step-by-step explanation:

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Ymorist [56]

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Step-by-step explanation:7c

3 0
3 years ago
Triangle PQR is similar to triangle XYZ. The length of PQ is one-half the length of XY. THe length of RP is 2 cm. Which proporti
e-lub [12.9K]

Answer:

ZX = 4cm

Step-by-step explanation:

Given

\triangle PQR similar to \triangle XYZ

PQ = \frac{1}{2}XY

RP = 2cm

Required

Find ZX

\triangle PQR similar to \triangle XYZ implies that, the following sides are similar

PQ \to XY

QR \to YZ

RP \to ZX

To find ZX, we make use of the following equivalent ratio

PQ : XY = RP : ZX

Where

PQ = \frac{1}{2}XY

RP = 2cm

So, we have:

\frac{1}{2}XY : XY = 2cm : ZX

Express as fraction

\frac{\frac{1}{2}XY }{ XY }= \frac{2cm }{ ZX}

\frac{1}{2}= \frac{2cm }{ ZX}

Make ZX the subject

ZX = 2 * 2cm

ZX = 4cm

5 0
3 years ago
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