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Svetradugi [14.3K]
3 years ago
8

How does natural selection affect populations?

Physics
1 answer:
Leto [7]3 years ago
6 0

Individuals that develop beneficial traits have a better chance of survival and individuals with less useful traits are weeded out through the process of natural selection. The greater the variety of traits that exist in a population, the greater the population's chance of survival.

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A particle is confined to the x-axis between x = 0 and x = 1 nm. The potential energy U = 0 inside this region and U is infinite
DiKsa [7]

Answer:

Explanation:

According to heisenberg uncertainty Principle

Δx Δp ≥ h / 4π , where Δx  is uncertainty in position , Δp is uncertainty in momentum .

Given

Δx = 1 nm

Δp ≥ h /1nm x  4π

≥ 6.6 x 10⁻³⁴ / 10⁻⁹ x  4 π

≥  . 5254 x ⁻²⁵

h / λ ≥  . 5254 x ⁻²⁵

 6.6 x 10⁻³⁴ /. 5254 x ⁻²⁵ ≥ λ  

12.56 x 10⁻⁹ ≥ λ  

longest wave length = 12.56 n m

6 0
3 years ago
The temperature of a plastic cube is monitored while the cube is pushed 3.4 m across a floor at constant speed by a horizontal f
Nesterboy [21]

Answer:

\Delta E_{floor} = 51 J

Explanation:

The work (W) done on the cube to be pushed across the floor is equal to the total thermal energy (ΔE) of the system:        

W = \Delta E_{T} = \Delta E_{cube} + \Delta E_{floor} (1)

Also, the work done on the cube by the horizontal force is giving by:

W = F \cdot d (2)  

<em>where F: force applied to the cube , d: displacement of the cube     </em>    

<em>By equaling the equations (1) and (2)</em>, we can find the thermal energy of the floor:  

\Delta E_{cube} + \Delta E_{floor} = F \cdot d

\Delta E_{floor} = F \cdot d - \Delta E_{cube}

\Delta E_{floor} = 20 N \cdot 3.4 m - 17 J  

\Delta E_{floor} = 51 J

 

So, the increase in the thermal energy of the floor is 51 J.  

Have a nice day!    

7 0
3 years ago
An effective early childhood curriculum can be​
kompoz [17]
An effective early childhood curriculum can be learning how to read and write. Without learning how to read, we wouldn’t be able to communicate through this app, or through online school. We wouldn’t know directions, and we wouldn’t be able to enjoy stories. If we didn’t know how to write, I would not be able to help you figure out the answer to this problem, and your teacher wouldn’t be able to grade anything. Think about it, you ir entire education is based of being able to read and write.


Hope this helps :)
6 0
3 years ago
A 300 g block connected to a light spring with a force constant of k = 3 N/m is free to oscillate on a horizontal, frictionless
Usimov [2.4K]

Answer:

Time period, T = 1.98 seconds

Explanation:

It is given that,

Mass of the block, m = 300 g = 0.3 kg

Force constant of the spring, k = 3 N/m

Displacement in the block, x = 3 cm

Let T is the period of the motion of the block. The time period of the block is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

T=2\pi \sqrt{\dfrac{0.3\ kg}{3\ N/m}}    

T = 1.98 seconds

So, the period of the motion of the block is 1.98 seconds. Hence, this is the required solution.

7 0
3 years ago
At what distance would the repulsive force between two electrons have a magnitude of 4.0 N?
borishaifa [10]

Answer:

7.6\cdot 10^{-15} m

Explanation:

The electrostatic force between two electrons is given by:

F=k\frac{e^2}{r^2}

where

k=8.99\cdot 10^9 Nm^2C^{-2} is the Coulomb's constant

e=-1.6\cdot 10^{-19}C is the electron charge

r is the distance between the two electrons

In this problem, we know F=4.0 N, so we can re-arrange the equation to calculate r:

r=\sqrt{\frac{ke^2}{F}}=\sqrt{\frac{(8.99\cdot 10^9)(-1.6\cdot 10^{-19})^2}{4.0 N}}=7.6\cdot 10^{-15} m

5 0
3 years ago
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