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quester [9]
3 years ago
13

In subduction, _____.

Physics
1 answer:
user100 [1]3 years ago
4 0

The answer is the less dense plate slides over the denser plate.

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The earth's radius is 6.37×106m; it rotates once every 24 hours. What is the earth's angular speed? What is the speed of a point
Zarrin [17]

Answer:

a) w = 7.27 * 10^-5 rad/s

b) v1 = 463.1 m/s

c) v1 = 440.433 m/s

Explanation:

Given:-

- The radius of the earth,  R = 6.37 * 10 ^6 m

- The time period for 1 revolution T = 24 hrs

Find:

What is the earth's angular speed?

What is the speed of a point on the equator?

What is the speed of a point on the earth's surface located at 1/5 of the length of the arc between the equator and the pole, measured from equator?

Solution:

- The angular speed w of the earth can be related with the Time period T of the earth revolution by:

                                  w = 2π / T

                                  w = 2π / 24*3600

                                  w = 7.27 * 10^-5 rad/s

- The speed of the point on the equator v1 can be determined from the linear and rotational motion kinematic relation.

                                 v1 = R*w

                                 v1 = (6.37 * 10 ^6)*(7.27 * 10^-5)

                                 v1 = 463.1 m/s

- The angle θ subtended by a point on earth's surface 1/5 th between the equator and the pole wrt equator is.

                                 π/2  ........... s

                                 x     ............ 1/5 s

                                 x = π/2*5 = 18°    

- The radius of the earth R' at point where θ = 18° from the equator is:

                                R' = R*cos(18)

                                R' = (6.37 * 10 ^6)*cos(18)

                                R' = 6058230.0088 m

- The speed of the point where θ = 18° from the equator v2 can be determined from the linear and rotational motion kinematic relation.

                              v2 = R'*w

                              v2 = (6058230.0088)*(7.27 * 10^-5)

                              v2 = 440.433 m/s

5 0
3 years ago
if a subatomic particle explodes in a particle accelerator before the collision what happenes ? anybody want to be friends
Anastaziya [24]

Answer: Sure!!!

Explanation:

8 0
3 years ago
Read 2 more answers
How are pupae, larvae, and nymphs similar? *Answer Fast!*
Goshia [24]

Answer:

They are all a cycle!

Explanation:

They just are all cycles.

5 0
3 years ago
What is the momentum of a 50 at a speed of 5m/s
aleksandr82 [10.1K]
50*5=250
Momentum will be 250kgm/s^2
5 0
3 years ago
A person is walking down the street maintain the same speed and direction. The person is accelerating.
balandron [24]

Answer:

no change in speed, therefore the body cannot be accelerated.  a=0

Explanation:

When a person is accelerating his speed must change, if the speed is in the same direction as the acceleration the speed increases and if the acceleration is in the opposite direction to the speed it decreases.

In this case there is no change in speed, therefore the body cannot be accelerated.

6 0
3 years ago
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