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quester [9]
3 years ago
13

In subduction, _____.

Physics
1 answer:
user100 [1]3 years ago
4 0

The answer is the less dense plate slides over the denser plate.

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A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a direction
Nuetrik [128]

Answer:

brainly.com/question/5055678

Explanation:

4 0
3 years ago
Car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver not
musickatia [10]

Answer:

Part A: t = v_0/a_0

Part B: t = v_0/a_0

Part C: v_0^2/a_0

Explanation:

Part A:

We will use the following kinematics equation:

v = v_0 + at\\0 = v_0 - a_0t\\t = \frac{v_0}{a_0}

Part B:

We will use the same kinematics equation:

v = v_0 + at\\v_0 = 0 + a_0t\\t = \frac{v_0}{a_0}

Part C:

The total time takes is 2t.

So the train moves a distance of

x = v_0(2t) = 2v_0(\frac{v_0}{a_0}) = \frac{2v_0^2}{a_0}

And the car moves a distance in Part A and in Part B:

d_A = v_0t + \frac{1}{2}at^2 = v_0(\frac{v_0}{a_0}) - \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{a_0} - \frac{v_0^2}{2a_0} = \frac{v_0^2}{2a_0}\\d_B = v_0t + \frac{1}{2}at^2 = 0 + \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{2a_0}

So the total distance that the car traveled is d = \frac{v_0^2}{a_0}

The difference between the train and the car is

x - d = \frac{2v_0^2}{a_0} - \frac{v_0^2}{a_0} = \frac{v_0^2}{a_0}

8 0
3 years ago
8 A car accelerates at a rate of 10m/s
zheka24 [161]

Answer:

From the First Law of Motion

Vf = Vi + at

"It reaches a speed of 52m/s" meaning the Final speed Vf=52

a(acceleration)=10m/s²

t=4s

Applying the formula

52=Vi + 10(4)

Vi = 52-40

Vi = 12m/s

5 0
3 years ago
What Is the mass of 7.50 mol of uranium
Andru [333]
Moles x Mol mass = mass. 
<span>Having looked it up, the mol.mass of U-238 is 238.03g/mol. </span>
<span>7.50 moles x 238.03g/mol. = 1,785.23g/mol</span>
5 0
4 years ago
Read 2 more answers
A certain kind of glass has an index of refraction of 1.660 for blue light of wavelength 420 nm and an index of 1.630 for red li
Bogdan [553]

Answer:

Explanation:

Using Snell's law

n₁ sinθ₁ = n₂ sinθ₂

for 420 nm wavelength

where n₁ = 1.00 ( refractive index of air) and θ₁ = 30° n₂ = 1.660

1.00 × sin 30° = 1.660 sinθ₂

sinθ₂ = 0.3012

θ₂ = sin⁻¹ 0.3012 = 17.53°

for 690 nm wavelength

n₁ sinθ₁ = n₂ sinθ₂

sinθ₂ = 0.5 / 1.630

θ₂ = sin⁻¹ 0.3067 = 17.86°

the angle between the two beam = 17.863° - 17.53° = 0.333°

7 0
3 years ago
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