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Liula [17]
4 years ago
14

The greatest speed recorded by a manned air breathing jet aircraft is 2,194 miles per hour. What is the speed in kilometers per

hour? 1.6 1,371 3,530 13,383
Physics
2 answers:
andre [41]4 years ago
7 0
The answer to this question is 3,530 :)
Travka [436]4 years ago
3 0

Answer:

 v = 3530 km / h

Explanation:

To make the change from thousands / h to km / h, we must reduce the magnitude

      1 mile = 1,609 km

So the reduction is

     v = 2194 miles / h (1,609 km / 1mile)

     v = 3530 km / h

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A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
Lemur [1.5K]

Answer:

a)   v = 0.9167 m / s,  b)  A = 0.350 m,  c)  v = 0.9167 m / s, d)  A = 0.250 m

Explanation:

a) to find the velocity of the wave let us use the relation

          v = λ f

the wavelength is the length that is needed for a complete wave, in this case x = 5.50 m corresponds to a wavelength

           λ = x

           λ = x

the period is the time for the wave to repeat itself, in this case t = 3.00 s corresponds to half a period

          T / 2 = t

           T = 2t

period and frequency are related

           f = 1 / T

           f = 1 / 2t

we substitute

           v = x / 2t

           v = 5.50 / 2 3

           v = 0.9167 m / s

b) the amplitude is the distance from a maximum to zero

          2A = y

           A = y / 2

           A = 0.700 / 2

           A = 0.350 m

c) The horizontal speed of the traveling wave (waves) is independent of the vertical oscillation of the particles, therefore the speed is the same

      v = 0.9167 m / s

d) the amplitude is

           A = 0.500 / 2

           A = 0.250 m

4 0
3 years ago
3. 500ml of 60oC water at is added to a beaker. Water’s specific heat is 4.186 J/g °C. You have 40ml of and unknown substance th
castortr0y [4]
Idkd djdjdbd djkdmdkdmkrkr r r r. R r
8 0
3 years ago
Find the weight of a 2000 kg elaphant
Vika [28.1K]

19,600 Newtons (about 4,400 pounds).

On Earth only.

Different in other places.

5 0
3 years ago
his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadi
zepelin [54]

Answer:

his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadily at 2.21 kg/m3 and 40 m/s and leaves at 0.762 kg/m3 and 192 m/s. The inlet area of the nozzle is 90 cm2.

determine (a) the mass flow rate through the nozzle, and (b) the exit area of the nozzle.

a)0.7956kg/s

b)5.437 × 10⁻³m²

Explanation:

The concepts related to the change of mass flow for both entry and exit is applied

The general formula is defined by

\dot{m}=\rho A V

Where,

\dot{m} = mass flow rate\\\rho = Density\\V = Velocity

values are divided by inlet(1) and outlet(2) by

\rho_1 = 2.21kg/m^3V_1 = 40m/s

A_1 = 90*10^{-4}m^2\\\rho_2 = 0.762kg/m^3\\V_2 = 192m/s

PART A) Applying the flow equation

\dot{m} = \rho_1 A_1 V_1\\\dot{m} = (2.21)(90*10^{-4})(40)\\\dot{m} = 0.7956kg/s

PART B) For the exit area we need to arrange the equation in function of Area, that is

A_2 = \frac{\dot{m}}{\rho_2 V_2}\\A_2 = \frac{0.7956}{(0.762)(192)}\\A_2 = 5.437*10^{-3}m^2

7 0
3 years ago
What's the difference mass and weight
yanalaym [24]

Answer:

Mass doesn't change.

Weight is measured based on gravitational pull.

Explanation:

4 0
3 years ago
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