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MA_775_DIABLO [31]

3 years ago

7

I need help please answer this correctly is the answer yes or no

1 answer:

Tema [17]3 years ago

3 0

Yes because 7 ketchup packets is 28 teaspoons

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Which details do the authors include to support the claim in this passage

Hunter-Best [27]

They site there sources or give information to prove why there point is correct

7 0

2 years ago

I need help ASAP!

sertanlavr [38]

Sin (x) = 12/13 this is because sine is opposite divided by hypotenuse.
cos (x) = 5/13 this is because cosine is adjacent divided by hypotenuse.
tan (x) = 12/5 this is because tangent is opposite divided by adjacent.

3 0

2 years ago

Find the slope of the line passing through the points(3, -4) and q(-7,1). then find the equation of the line passing through tho

IRISSAK [1]

Slope is -4-1/-7-3= -5/-10=1/2 it is y2-y1/x2-x1
the equation is y-y1= m(x-x1)= y-(-4) =1/2(x-3) =y+4 =1/2(x-3)

5 0

2 years ago

The remainder after diving x^4+3x^3-8x^2+5x-9 by x+5 is ____.

raketka [301]

Use the polynomial remainder theorem. It says that a polynomial $f(x)$ has remainder $f(c)$ upon division by $x-c$ .

Here we have

$f(x)=x^4+3x^3-8x^2+5x-9$

and $c=-5$ , so the remainder is

$f(-5)=(-5)^4+3(-5)^3-8(-5)^2+5(-5)-9=\boxed{16}$

6 0

3 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

4 0

2 years ago