Question

Suppose that ym has length 12 in. and its distance from point L is 5 in. Find the radius of ⊙L to the nearest tenth.

Answer 1

Answer:

The radius of circle L is $7.8\ in$

Step-by-step explanation:

Remember that a line that passes through the center divide the circle into two equal parts

YV=VM=6 in

VL is perpendicular to YM

so

The triangle VLM is a right triangle

The radius is equal to LM ----> hypotenuse of the triangle VLM

Applying the Pythagoras Theorem

$LM^{2}=VM^{2}+VL^{2}$

substitute the given values

$LM^{2}=6^{2}+5^{2}$

$LM^{2}=61$

$LM=7.8\ in$