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3 years ago

The radio of boys to girls is 3:4. There were 60 girls at the dance. How many boys were at the dance?

Mathematics

2 answers:

IRINA_888 [86]3 years ago

5 0

Answer: There are 45 boys

Step-by-step explanation:

3:4

60÷4=15

15×3

=45

bagirrra123 [75]3 years ago

3 0

<h2><u>Answer:</u></h2><h2>a. Use a proportion comparing boys to girls at the dance. boys/girls=3/4=x/60</h2><h2>Solve the proportion by cross-multiplying, setting the cross-products equal to each other, and solving as shown below.</h2><h2>(3)(60) = 4x</h2><h2>180 = 4x</h2><h2>180/4=4x/4</h2><h2>45=x</h2><h2>There were 45 boys at the dance.</h2><h2><u></u></h2><h2><u>Thank you </u></h2><h2><u>sunshinemadison101</u></h2>

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5ab^2 - 12a^2b + 3ab + ab^2 + 4a^2b

Agata [3.3K]

Answer:

(a) 6ab² - 8a²b + 3ab

Step-by-step explanation:

Given: 5ab² - 12a²b + 3ab + ab² + 4a²b

In this question, we will be combining like terms.

What are like terms?

Like terms are terms with the same variables and power. For example, 2x and 4x, as well as 2a² and 4a².

Combine like terms:

5ab² - 12a²b + 3ab + ab² + 4a²b

(5ab² + ab²) + (-12a²b + 4a²b) + 3ab

6ab² - 8a²b + 3ab

4 0

2 years ago

Richard and Teo have a combined age of 26 . Richard is5 years older than twice Teo's age. How old are Richard and Teo?

loris [4]

Answer:Teo's age = 7 years ,Richard's age = 19 years

Step-by-step explanation:

Step 1

Let Teo's age be represented as x

Such that Richard 's age = 5 + 2x

and their combined ages equaling 26 can be expressed as

x + 5+ 2x = 26

Step 2 --- SOLVING

x + 5+ 2x = 26

3x+ 5= 26

3x= 26-5

3x= 21

x = 21/3

x = 7

Teo's age = 7 years

Richard's age = 5+2x= 5 + 14= 19 years

8 0

3 years ago

An irrigation system (sprinkler) has a parabolic pattern. The height, in feet, of the spray of water is given by the equation h(

jasenka [17]

9514 1404 393

Answer:

7.5 ft
32.5 ft, 5 ft
10.7 ft

Step-by-step explanation:

a) The starting height is h(0) = 7.5 feet, the constant in the quadratic function.

The irrigation system is positioned <u> 7.5 </u> feet above the ground

b) The axis of symmetry for quadratic ax^2 +bx +c is x = -b/(2a). For this quadratic, that is x=-10/(2(-1)) = 5. This is the horizontal distance to the point of maximum height. The maximum height is ...

h(5) = (-5 +10)(5) +7.5 = 32.5 . . . feet

The spray reaches a maximum height of <u> 32.5 </u> feet at a horizontal distance of <u> 5 </u> feet from the sprinkler head.

c) The maximum distance will be √32.5 + 5 ≈ 10.7 ft.

The spray reaches the ground at about <u> 10.7 </u> feet away.