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3 years ago

The radio of boys to girls is 3:4. There were 60 girls at the dance. How many boys were at the dance?

Mathematics

2 answers:

IRINA_888 [86]3 years ago

5 0

Answer: There are 45 boys

Step-by-step explanation:

3:4

60÷4=15

15×3

=45

bagirrra123 [75]3 years ago

3 0

<h2><u>Answer:</u></h2><h2>a. Use a proportion comparing boys to girls at the dance. boys/girls=3/4=x/60</h2><h2>Solve the proportion by cross-multiplying, setting the cross-products equal to each other, and solving as shown below.</h2><h2>(3)(60) = 4x</h2><h2>180 = 4x</h2><h2>180/4=4x/4</h2><h2>45=x</h2><h2>There were 45 boys at the dance.</h2><h2><u></u></h2><h2><u>Thank you </u></h2><h2><u>sunshinemadison101</u></h2>

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Please help! I will rank and thank! :)

Leokris [45]

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6 0

3 years ago

This is due tomorrow if someone could help me that would be great <3

kifflom [539]

<u>Hope this helped!</u>

<u>First Row</u>

$\frac{5}{18}$

$\frac{10}{21}$

$\frac{9}{40}$

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5 0

2 years ago

Which equation represents the perpendicular bisector of the given line segment?

In-s [12.5K]

Answer:

Option D. $x=10$

Step-by-step explanation:

step 1

Find the midpoint of the given line segment

we know that

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

$A(5,10),B(15,10)$

substitute the values

$M=(\frac{5+15}{2},\frac{10+10}{2})$

$M=(10,10)$

step 2

Find the equation of the perpendicular bisector

we know that

The equation of a perpendicular bisector is equal to the x-coordinate of the midpoint, because is a vertical line (parallel to the y-axis)

therefore

the equation is equal to

$x=10$

7 0

3 years ago

Read 2 more answers

Please answer correctly !!!!! Will mark brainliest answer !!!!!!!!!!

AnnZ [28]

Answer:

type 2 in the first box,

13/4 in the second box, and

-9/8 in the third one

Step-by-step explanation:Notice that you are asked to write the following quadratic expression in vertex form, so you need to find the "x" value of the vertex, and then the "y" value of the vertex:

$x_{vertex}= -b/2a$