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3 years ago

The radio of boys to girls is 3:4. There were 60 girls at the dance. How many boys were at the dance?

Mathematics

2 answers:

IRINA_888 [86]3 years ago

5 0

Answer: There are 45 boys

Step-by-step explanation:

3:4

60÷4=15

15×3

=45

bagirrra123 [75]3 years ago

3 0

<h2><u>Answer:</u></h2><h2>a. Use a proportion comparing boys to girls at the dance. boys/girls=3/4=x/60</h2><h2>Solve the proportion by cross-multiplying, setting the cross-products equal to each other, and solving as shown below.</h2><h2>(3)(60) = 4x</h2><h2>180 = 4x</h2><h2>180/4=4x/4</h2><h2>45=x</h2><h2>There were 45 boys at the dance.</h2><h2><u></u></h2><h2><u>Thank you </u></h2><h2><u>sunshinemadison101</u></h2>

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Answer:

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Step-by-step explanation:

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3 years ago

A sample of marble has a volume of 6 cm3 and a density of 2.76 g/cm3. What is its mass?

Drupady [299]

Answer:

$16.56\ g$

Step-by-step explanation:

we know that

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mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(U |D ) = 0.198$

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Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

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Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

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$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

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$P(O | B) = \frac{T_z}{ T}$

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$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

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3 years ago

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Answer:

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The building will be $\boxed{\textbf{3 in}}$ tall in the scale drawing.

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3 years ago