You have done something incorrectly. such as your data.
Answer:
Two point charges are separated by 6.4 cm . The attractive force between them is 10 N .
units.
Explanation:
Answer:
a) -41.1 Joule
b) 108.38 Kelvin
Explanation:
Pressure = P = 290 Pa
Initial volume of gas = V₁ = 0.62 m³
Final volume of gas = V₂ = 0.21 m³
Initial temperature of gas = T₁ = 320 K
Heat loss = Q = -160 J
Work done = PΔV
⇒Work done = 290×(0.21-0.62)
⇒Work done = -118.9 J
a) Change in internal energy = Heat - Work
ΔU = -160 -(-118.9)
⇒ΔU = -41.1 J
∴ Change in internal energy is -41.1 J
b) V₁/V₂ = T₁/T₂
⇒T₂ = T₁V₂/V₁
⇒T₂ = 320×0.21/0.62
⇒T₂ = 108.38 K
∴ Final temperature of the gas is 108.38 Kelvin
<h2>Answer:</h2>
The diagram is not showing the second law of thermodynamics. It is the demonstration of 1st law of thermodynamics.
<h3>Explanation:</h3>
Second law of thermodynamics describes the entropy of the system increase with time, it does not decrease with time. It is constant for ideal systems.
While in first law of thermodynamics, it is stated that the energy of a system can not be lost but it is transferred from one form to other form.
And in this picture, it is shown that the energy released from heat source to cold sink is used in doing work.
Work and heat are forms of energy.
