The height of the table above the ground is 0.45 m.
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Horizontal velocity (u) = 3 m/s
- Time (t) = 0.3 s
- Acceleration due to gravity (g) = 10 m/s²
- Height (h) =?
<h3>How to determine the height </h3>
The height of the table can be obtained by using the following formula:
h = ½gt²
h = ½ × 10 × 0.3²
h = 5 × 0.09
h = 0.45 m
Thus, the height of the table is 0.45 m
Learn more about motion under gravity:
brainly.com/question/26275209
Answer:
9) This is a case of deceleration
10)-0.8 ms-2
b) acceleration is the change in velocity with time
11)
a) 100 ms-1
b) 100 seconds
12) 10ms-1
13) more information is needed to answer the question
14) - 0.4 ms^-2
15) 0.8 ms^-2
Explanation:
The deceleration is;
v-u/t
v= final velocity
u= initial velocity
t= time taken
20-60/50 =- 40/50= -0.8 ms-2
11)
Since it starts from rest, u=0 hence
v= u + at
v= 10 ×10
v= 100 ms-1
b)
v= u + at but u=0
1000 = 10 t
t= 1000/10
t= 100 seconds
12) since the sprinter must have started from rest, u= 0
v= u + at
v= 5 × 2
v= 10ms-1
14)
v- u/t
10 - 20/ 25
10/25
=- 0.4 ms^-2
15)
a=v-u/t
From rest, u=0
8 - 0/10
a= 8/10
a= 0.8 ms^-2
You are correct it is translucent because opaque let’s no light through but transparent lets almost all light through
Johannes Kepler- he did it by observing the ‘Tycho Brahe’. His 3rd law was published 10 years later to his first two laws.
Answer:
No concave lens cannot be used to make hand lens because in hand Lens we use convex lens so as to converge the rays of the light After refraction and helps to produce a magnified image of an object.
Hope it will help you :)❤
