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Damm [24]
3 years ago
11

Me ajudem por favor ​

Physics
1 answer:
svetlana [45]3 years ago
8 0

Answer:

dd

Explanation:

jcfergygtrtttttttttttttttt

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The forces acting on a ball sitting on the ground are
Dmitrij [34]
If you were a ball sitting on a field and someone kicked you, a force would have acted on you. ... Those forces would include gravity, the force of air particles hitting your body from all directions (as well as from wind), and the force being exerted by the ground (called the normal force).
3 0
2 years ago
If a body of 2kg mass is at a distance of 7200km from the center of the earth .What
wlad13 [49]

None of the choices is correct.

== The Earth's radius is 6,371 km.  That's how far you are from the center of the Earth when you're on the ground.

== The acceleration of gravity on the ground is 9.8 m/s² .

== The acceleration of gravity varies inversely as the square of the distance from the center of the Earth.  So, at 7,200 km from the center, it's

(9.8 m/s²) · (6371km/7200km)² .

Stuffing this through your cakulator, you'll get  <em>7.67 m/s²</em> .

3 0
3 years ago
Backpackers often use canisters of white gas to fuel a cooking stove's burner. If one canister contains 1.45 L of white gas, and
lorasvet [3.4K]

Answer: One canister contains 1.03 Kg of fuel,

Explanation:

The density is defined as the relation between the mass and the volume p=\frac{m}{v}

First of all you need to have the same units for volume and density, so:

For the volume,

1.45 L * \frac{1.10*10^{-3}m^{3}  }{1 L} = 1.45 *10^{-3} m^{3}

For the density,

p = 0.710\frac{g}{cm^{3} } *\frac{1cm^{3} }{1*10^{-6}m^{3}  }*\frac{1 Kg}{1*10^{3}g } = 710\frac{Kg}{m^{3} }

From the density equation we have m=p*v, so:

710\frac{Kg}{m^{3} } *1.45*10^{-3} m^{3} = 1.03Kg

4 0
4 years ago
The droplets on a glass of ice water are a result of water vapor releasing energy and changing to water droplets.
olya-2409 [2.1K]

Answer:

B. condensation

Explanation:

hope this helps

4 0
3 years ago
Read 2 more answers
An alligator swims to the left with a constant velocity of 5 S/M
Goshia [24]

Answer:

t = 0.85[s]

Explanation:

To solve this problem we must make a complete description of this. By doing an internet search, we find the description of this problem as if of the question.

<u>Description</u>

<u />

"An alligator swims to the left with a constant velocity of 5 m s when the alligator season a bird straight ahead the alligator speeds up with a constant acceleration of 3 m/s^2 leftward until it reaches a final velocity of 35 Ms left work how many seconds does it take the alligator to speed up from 5 m/s to 35 m/s".

To solve this problem we must identify the initial data:

v0 = initial velocity = 5 [m/s]

a = acceleration = 3 [m/s^2]

vf = final velocity = 35[m/s]

t = time = ?

Using the following kinematic equation, we can find the time that is required.

v_{f}=v_{0}+a*t\\35=5+35*t\\t=\frac{35-5}{35} \\t=0.85[s]

8 0
4 years ago
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