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Taya2010 [7]
3 years ago
15

How does the ocean play an important role in climate and climate change? Keep answer related to the specific heat capacity of wa

ter
Physics
1 answer:
nata0808 [166]3 years ago
3 0
One way that the world's ocean affects weather and climate is by playing an important role in keeping our planet warm. ... The ocean doesn't just store solar radiation; it also helps to distribute heat around the globe. When water molecules are heated, they exchange freely with the air in a process called evaporation.
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An aluminum rod is designed to break when it is under a tension of 600 N. One end of the rod is connected to a motor and a 12-kg
9966 [12]

Answer:

17 m/s

Explanation:

Given:

Tension = 600 N

Mass of object, M= 12 kg

Radius, r = 5.78 m

Required:

Find the speed the rod will break

Here, the motor is continuously increased. To find the speed the rod will break (speed of centripetal force), we have:

Tension = Centripetal force

Where centripetal force = \frac{mv^2}{r}

Therefore,

T = \frac{mv^2}{r}

Make v subject of the formula:

v = \sqrt{\frac{T*r}{m}}

= \sqrt{\frac{600*5.78}{12}}

= \sqrt{\frac{3468}{12}

= \sqrt{289}

= 17 m/s

Speed the rod will break is 17 m/s.

4 0
4 years ago
In 1932, James Chadwick bombarded beryllium-9 with alpha particles. One product was a neutron. This led to the direct experiment
Fed [463]

Answer:  The other product of Chadwick's nuclear reaction was carbon-12.

Explanation:

The isotopic representation of an atom is: _Z^A\textrm{X}

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given reaction:

^{9}_{4}\textrm{Be}+^4_2\textrm{He}\rightarrow ^{A}_{Z}\textrm{Kr}+^1_0\textrm{n}

To calculate A:

Total mass on reactant side = total mass on product side

9 + 4= A + 1

A = 12

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

4 + 2 = Z + 0

Z = 6

The isotopic symbol is _{6}^{12}\textrm{C} . Thus The other product of Chadwick's nuclear reaction was carbon-12.

7 0
3 years ago
A 25 pF parallel-plate capacitor with an air gap between the plates is connected to a 100 V battery. A Teflon slab (dielectric c
adoni [48]

Answer:

The change in the charge on the positve plate when the Teflon is inserted is +2.5 nC.

Explanation:

  • It can be showed that the capacitance of a parallel-plate capacitor, can be expresssed as follows:

       C = \frac{\epsilon*A}{d}

  • Where ε, is the dielectric constant of the material that fills the space between plates.
  • When this space is filled with air, ε= ε₀ = 8,85*10⁻¹² F/m.
  • At the same time, the capacitance of a capacitor, by definition, is as follows:

       C =\frac{Q}{V}

  • If we insert a Teflon slab, in such a way that fills completely the gap between the plates, all other parameters being equal, if ε = 2*ε₀, this means that C₂ = 2* C₁. = 50 pF
  • As V₂=V₁ (due to the capacitor remains connected to the same battery) the charge must be the double, so Q₂ = 2* Q₁ = 5 nC.
  • So, the change in the charge of the positive plate is +2.5 nC.
3 0
3 years ago
A particle travels along a straight line with a velocity v = (12 - 3t) m/s, where t is in seconds. When t = 1 s, the particle is
Simora [160]

Answer:

(1).The acceleration is -24 m/s²

The total distance is 912 m.

(2). The distance traveled before it stop is 78 m.

Explanation:

Given that,

Velocity = (12-3t^2) m/s

When t = 1 s, the particle is located 10 m to the left of the origin.

We need to calculate the acceleration at t = 4 sec

Using formula of acceleration

a=\dfrac{dv}{dt}

Put the value of v

a=\dfrac{d}{dt}(12-3t^2)

a=-6t

Put the value of t

a=-6\times4

a=-24\ m/s^2

The displacement from t = 0,t = 10 s, and the distance the particle travels during this time period.

We need to calculate the distance

Using formula of distance

ds=v\ dt

\int_{-10}^{s}=\int_{1}^{t}{v}dt

Put the value of v

\int_{-10}^{s}=\int_{1}^{t}{ (12-3t^2)}dt

s+10=12t-t^3-11

s=12t-t^3-21

At t = 0,

s_{t=0}=-21

At t = 10,

s_{t=10}=12\times10-10^3-21

s_{t=10}=-901

The displacement is

\Delta s=-901-(-21)

\Delta s=-880\ m

The distance at t= 2 sec

s_{t=2}=12\times2-2^3-21

s_{t=2}=-5

The total distance will be,

s_{T}=(21-5)+(901-5)

s_{T}=912\ m

(2). We need to calculate the distance at 2 sec

Using equation of motion

s=ut-\dfrac{1}{2}at^2

Put the value into the formula

s=27\times 2+\dfrac{1}{2}\times6\times(2)^3

s=78\ m

Hence, (1).The acceleration is -24 m/s²

The total distance is 912 m.

(2). The distance traveled before it stop is 78 m.

3 0
3 years ago
A car going 50 miles/hr accelerates to pass a truck. 5 seconds later the car is going 80 miles/hr. What is the acceleration of t
mariarad [96]
 It would be 6 mph<span>/s 11</span>
5 0
3 years ago
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