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Juli2301 [7.4K]
3 years ago
5

What is the range of this set of data? 111.97, 63, 84, 100, 119,72

Mathematics
2 answers:
irina1246 [14]3 years ago
7 0
56. To find range you find the difference between the highest and lowest values in your set of numbers. Arrange your set of numbers from least to greatest. Take your lowest number and subtract it from your highest number, then you will have your range.
Reika [66]3 years ago
3 0

Answer:

56

Step-by-step explanation:

The range of a data set is the difference between the largest and the smallest values in that data set. In this case, the largest value in the data set is 119, and the smallest is 63. 119-63=56, which is the range. Hope this helps!

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-21x+31 this is the answer you were looking for
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Evan saves $2 for every $5 he earns mowing lawns. How much will Evan have saved when he has earned $150?
Lesechka [4]

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he will have saved 45$

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Read 2 more answers
How many more festivals had 18 to 23 countries represented than 0 to 5 countries represented?
kari74 [83]

Answer:

3

Step-by-step explanation:

Here, by reading the histogram, we will provide answer for the question asked.

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6 0
2 years ago
The length of time for one individual to be served at a cafeteria is a random variable having an exponential distribution with a
Leya [2.2K]

Answer:

a) 0.25

b) 52.76% probability that a person waits for less than 3 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \lambda e^{-\lambda x}

In which \lambda = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

In this question:

m = 4

a. Find the value of λ.

\lambda = \frac{1}{m} = \frac{1}{4} = 0.25

b. What is the probability that a person waits for less than 3 minutes?

P(X \leq 3) = 1 - e^{-0.25*3} = 0.5276

52.76% probability that a person waits for less than 3 minutes

3 0
3 years ago
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