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2 years ago

I need help plz I don't get this problem

Mathematics

1 answer:

OlgaM077 [116]2 years ago

5 0

To find the answer you need to write equivalent fractions with larger denominators. If you multiply each fraction by 3/3 then your equivalent fractions would be

3/5 × 3/3 = 9/15
4/5 × 3/3 = 12/15

Now we have two fractions that are equivalent to the original fractions and we can easily see that 2 fractions between 9/15 and 12/15 would be...

10/15 and 11/15

(10/15 can reduce to 2/3 so your answers could also be 2/3 and 11/15)

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2 years ago

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2 years ago

Rewrite 2tan3x in terms of tanx

blsea [12.9K]

$2\tan3x=2\tan(2x+x)=\dfrac{2\tan2x+2\tan x}{1-\tan2x\tan x}$

Use the same identity to expand $\tan2x$ .

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$\implies2\tan3x=\dfrac{2\dfrac{2\tan x}{1-\tan^2x}+2\tan x}{1-\dfrac{2\tan x}{1-\tan^2x}\tan x}$
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3 years ago