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1 year ago

Solve the following equation4+2y=-9+2y

Mathematics

1 answer:

bulgar [2K]1 year ago

6 0

Answer:

${ \tt{4 + 2y = - 9 + 2y}} \\ \\ { \sf{2y - 2y = - 9 - 4}} \\ \\ { \sf{0y = - 13}}$

Hence no real values for y { y ≠ ∅ }

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3 years ago

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Find the width of a rectangle 25 feet and the perimeter is 80

lukranit [14]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - a rectangle with length 25 feet and perimeter 80 feet

To calculate - width of the rectangle

We know that ,

$\bold{Perimeter \: of \: rectangle = 2(l + b)} \\$

where b = width / breadth of rectangle

‎ ‎ ‎

substituting the values in the formula stated above ,

$\bold{80 = 2(25 + b)} \\ \\\bold{ \implies \: 25 + b = \cancel \frac{80}{2} } \\ \\ \bold{\implies \: 25 + b = 40 }\\ \\ \bold{\implies \: b = 40 - 25 }\\ \\\bold{ \implies \: b = 15 \: feet}$

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2 years ago

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A research company desires to know the mean consumption of meat per week among people over age 40. A sample of 610 people over a

Papessa [141]

Answer: $(3.0,\ 3.2)$

Step-by-step explanation:

Confidence interval for population mean is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$ (1)

, where $\overline{x}$ = Sample mean

$z_{\alpha/2}$ = Critical z-value

$\sigma$ = Population standard deviation.

n= Sample size.

As per given , we have

n= 610

$\sigma=1.1$

$\overline{x}=3.1$

Significance level for 85% confidence : $\alpha=1-0.85=0.15$

By z-table critical two tailed z-value : $z_{\alpha/2}=z_{0.075}=1.44$

Put all values in (1) , we get

$3.1\pm 1.44\dfrac{1.1}{\sqrt{610}}$

$3.1\pm 1.44\dfrac{1.1}{24.698}$

$3.1\pm 0.064$

$=(3.1-0.064,\ 3.1+0.064)=(3.036,\ 3.164)\approx(3.0,\ 3.2)$

Hence, the 85% confidence interval for the mean consumption of meat among people over age 40. = $(3.0,\ 3.2)$

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3 years ago