Answer:
1) The probability that the mean mpg for a random sample of 25 light vehicles is 0.042341.
2) between 20 and 25 --> 21-25/2.9 = -1.38
Step-by-step explanation:
Problem #1:
- Using the z-score formula, z = (x-μ)/σ/n, where x is the raw score = 20 mpg,μ is the population mean = 21 mpg , σ is the population standard deviation = 2.9, n = random number of samples.
<h3><u>X < 20</u></h3>
- = z = 20 - 21/2.9/√25
- = z = -1/2.9/5
- = z = -1.72414
<h2><u><em>Now</em></u></h2>
<em>P-value from Z-Table:</em>
<h3><u>P(x<20) = 0.042341</u></h3>
Problem #2:
<h3>21-25/2.9 = -1.38</h3>
Answer:
C.(3|-4)
Step-by-step explanation:
Given the vector:
![\left[\begin{array}{ccc}4\\3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C3%5Cend%7Barray%7D%5Cright%5D)
The transformation Matrix is:
![\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C-1%260%5Cend%7Barray%7D%5Cright%5D)
The image of the vector after applying the transformation will be:
![\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C-1%260%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C3%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2A4%2B1%2A3%5C%5C-1%2A4%2B0%2A3%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C-4%5Cend%7Barray%7D%5Cright%5D)
The correct option is C
Answer:
The answer for this question is-4
