What is the center of a circle with the equation (x - 6)2 + (y + 2)2 = 9?
1 answer:
Answer:
B. (6,-2)
Step-by-step explanation:
The equation of a circle is (x-h)^2+(y-k)^2=r^2
The center of the circle is (h,k)
So, in this problem, h is 6 and k is -2, so the center of this circle is (6,-2).
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I hope this helps!
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