a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as
... c = k·s² + m·s + n
Filling in the given values gives three equations in k, m, and n.
Subtracting each equation from the one after gives
Subtracting the first of these equations from the second gives
Using the next previous equation, we can find m.
Then from the first equation
[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]
There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with
... c = 0.01s² - s + 37
b) At 150 kph, the cost is predicted to be
... c = 0.01·150² -150 +37 = 112 . . . cents/km
c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.
d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.
Answer:
w < 82/5
Step-by-step explanation:
5w + 8 < 90
5w < 82
w < 82/5
Answer:
O is largest, C is medium, and T is smallest
Step-by-step explanation:
You need to pay close attention to the side length. The higher the length, the smaller the angle.
:)
Answer:
The correct option is C.
Step-by-step explanation:
According to the question given in the attached picture:
Event A = a customer buys a mouse
Event B = A customer buys a bird
P(A or B) = 0.25
Now have a look at the probability P(A or B). Here or means either..Its means that the customer will purchase either a mouse or a bird. That means that there is 0.25 or 25% probability that the customer will purchase either a mouse or a bird. In this case there are only 3 choices, which are: the customer will either purchase a mouse, a bird or a reptile because the pet store has only these three possible outcomes. We are not told that how much of each animal they have. Thus the probability that the customer will either purchase either a mouse or a bird is 0.25 or 25%. That means that the probability of either purchasing a mouse or a bird is added together which is 0.25 or 25%
Thus the correct option is C....
