Answer:
0.7
Step-by-step explanation:
67/10 is the same as 6.7 when you subtract the 0.7 you will remain with 6
9514 1404 393
Answer:
True; about 120° CCW rotation about Q
Step-by-step explanation:
Triangle A'B'C' appears to be congruent to triangle ABC and about the same distance from point Q. The angle of rotation from ABC to A'B'C' appears to be about 120° counterclockwise when measured using a geometry program.
Triangle A'B'C' is the image of triangle ABC under rotation about 120° CCW about point Q.
_____
<em>Additional comment</em>
If choices of rotation angle are ±135° or ±165°, the best choice would be ...
135°
Answer:
EF = 6.6
Step-by-step explanation:
Since ABCD is similar to EFGH, then EH is similar to AD. So, we can solve by first dividing 12 by 2 (EH by AD). The quotient of this is 6. This tells us that quadrilateral EFGH is 6 times larger than quadrilateral ABCD, since they are similar. So, with this and the measurement of AB (which is similar to EF), we can now solve for EF. We simply multiply 1.1 (the measurement of AB) by 6 (how many times larger EFGH is compared to ABCD). The product of this is 6.6, our final answer.
Answer:
Simplify
x
=
35.99
dollar
11.33
dollar
.
x
=
3.1765225
Step-by-step explanation:
Answer:
37.7
Step-by-step explanation:
EF and ED define the Tangent of D
Tan(37) = side opposite D / side adjacent to D
Opposite means a line (FE) that is not connected to the angle. It is never the longest line (hypotenuse) in a Right Triangle
Adjacent means the leg that is connected to the angle, but is not the hypotenuse.
Tan(D) = opposite over adjacent
Opposite = x
Adjacent = 50
Tan(37) = 0.7536 rounded to 4 places, but I've kept the exact value in my calculator.
0.7536 = x / 50 Multiply both sides by 50
0.7536*50 = x
x = 37.6777
The nearest 1/10 is 37.7
