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UkoKoshka [18]
3 years ago
11

725 tickets were sold for a game for a total of $1,487.50. If adult tickets sold for $2.50 and children's tickets sold for $1.50

, how many of each kind of ticket were sold?
Mathematics
2 answers:
lakkis [162]3 years ago
5 0

Answer: 400 adult tickets and 325 children's tickets were sold.

Step-by-step explanation:

Let x represent the number of adult tickets that were sold.

Let y represent the number of children's tickets tickets that were sold.

725 tickets were sold for the game. It means that

x + y = 725

If adult tickets sold for $2.500 and children's tickets sold for $1.50 and the total amount for which the tickets were sold $1,487.50, it means that

2.5x + 1.5y = 1487.50- - - - - - - - -1

Substituting x = 725 - y into equation 1, it becomes

2.5(725 - y) + 1.5y = 1487.50

1812.5 - 2.5y + 1.5y = 1487.50

- 2.5y + 1.5y = 1487.50 - 1812.5

- y = - 325

y = 325

x = 725 - y = 725 - 325

x = 400

weqwewe [10]3 years ago
3 0

Answer:

  • 400 adult tickets
  • 325 children's tickets

Step-by-step explanation:

Let x represent the number of adult tickets sold. Then 725-x is the number of children's tickets sold, and the total revenue is ...

  2.50x +1.50(725 -x) = 1487.50

  1.00x + 1087.50 = 1487.50 . . . . . eliminate parentheses

  x = 400 . . . . . . . . . . . . . . . . . . . . . subtract 1087.50

There were 400 adult tickets and 325 children's tickets sold.

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4 years ago
Can anyone please help!!!
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Answer:

Question 9

(a) The distance, Jalaj walks in one day is 4.4 km

(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8

Question 10

(b) The difference between the largest and smallest areas is 2,400 m²

Step-by-step explanation:

Question 9

(a) The distance Jalaj walks in 5 days = 22 km

Whereby Jalaj walks equal distance every day, we have;

The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day

The distance, Jalaj walks in one day = 4.4 km

(b) The amount he raises for every kilometer he walks = $1.60

The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60  = $8

Question 10

(b) The given side length of the square = 120 meters to the nearest 10 meters

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The maximum dimension for the side length of the square = 120 + 10/2 = 125

The largest possible area of the square, A_l = 125 m × 125 m = 15,625 m²

The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m

The smallest possible area of the square, A_s = 115 m × 115 m = 13,225 m².

The difference between the largest and smallest areas, A_l - A_s = 15,625 - 13,225 = 2,400 m².

8 0
3 years ago
Use the elimination method to solve the system of equations.Choose the correct ordered pair. x+y=8 x-y=6
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Answer:

Solution (7,1)

Step-by-step explanation:

Use the elimination method

x + y=8

x - y=6

--------------Add

2x = 14

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Substitute x = 7 into x + y=8

7 + y=8

y = 8 - 7

y = 1

Solution (7,1)


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