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3 years ago

ASAP kinda need help atm if anyone can solve this?

Mathematics

1 answer:

stepladder [879]3 years ago

7 0

Answer:

b^5

(b to the power of 5)

Step-by-step explanation:

To put it in the easiest way, you're doing 11 - 6

To put it in a more complex way, you're doing (1/b*b*b*b*b*b*b) * (b*b*b*b*b*b*b*b*b*b*b*) which then would equal b*b*b*b*b

which in both cases it would be b^5

Hope it helped

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Becky and claire went trick or treating.At the end of the night ,they combined their candy and found they each had four large ca

Natalija [7]

Answer:

Well, You possibly did all the math depending on the question. But if it was subtraction that means there's one candy bar left

step-by-step explanation:

I hope this helped in any way!

8 0

3 years ago

Which of the following expressions are equivalent to -19/8 x(-50)

dmitriy555 [2]

1. Move the negative sign to the left.

- $\frac{19}{8}$ $X$ *-50

2. Use this rule: $\frac{a}{b}$ $*$ $\frac{c}{d}$ = $\frac{ac}{bd}$

- $\frac{19x*-50}{8}$

3. Simplify - $\frac{-950x}{8}$

4. Move the negative sign to the left.

-(-950x/8)

5. Simplify 950x/8 to 475x/4

6. Remove parentheses.

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2 years ago

If ABCD ~ EHFG what do you know about the corresponding sides? Be specific.

melomori [17]

The answer for this is the last option

6 0

3 years ago

I need help with two algebra problems please!

postnew [5]

Fisrst one is just add the functions

(f+g)(x)=f(x)+g(x)=
8x^2+16x+6+x^3-3x^2-9=
(f+g)(x)=x^3+5x^2+16x-3

multiply
ok

f(x)g(x)=(x^3-4x+2)(x^2+2)
just multiply and expand yourself because I don't have my graphing calculator with me right now

8 0

3 years ago

Suppose you were to draw all possible samples of size 36 from a large population with a mean of 650 and a standard deviation of

Lady_Fox [76]

Answer:

By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 650 and a standard deviation of 24.

This means that $\mu = 650, \sigma = 24$ .

Sample of 36:

This means that $n = 36, s = \frac{24}{\sqrt{36}} = 4$

What is the shape of the sampling distribution you would expect to produce?

By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.

7 0

3 years ago