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CaHeK987 [17]
2 years ago
9

Need help on these problems plz its for a grade

Mathematics
2 answers:
Ronch [10]2 years ago
6 0

C: 390 because 5 times 6 is 30 and 30 times 13 is 390

irina [24]2 years ago
4 0

Answer:

C. 390 Cubic units

5 * 6 * 13 = 390 cubic units

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Makovka662 [10]
What line kkkkkkkkkkkkkk

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3 years ago
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PLZ HURRY i need this for test if you have the answers for all questions plz put the test is for plato algebra A1 unit3 post tes
elena-14-01-66 [18.8K]

Explanation is in the file

tinyurl.com/wpazsebu

7 0
3 years ago
56 points for whoever answers correctly !
vladimir2022 [97]

We need to use what we know about rectangles to get:

1)

  • Total length = 2*W + 8ft
  • Total width = W + 8ft

2) area = 2*W^2 + 24ft*W + 64ft^2

<h3>Working with rectangles:</h3>

We know that rectangles are defined by two measures, width W and length L.

Here we do know that the length of the pool is twice the width, and the width is W, then the length of the pool is:

L = 2*W

And we also have a sidewalk of 4ft all around the pool, now we want to get:

1) The total length and the total width.

This will be equal to the length/width of the pool <u>plus twice the width of the sidewalk</u> (we add it twice because is in both ends) then we have:

  • Total length = L + 2*4ft = 2*W + 8ft
  • Total width = W + 2*4ft = W + 8ft

2) Now we want to get an expression for the total area of the pool.

Remember that for a rectangle the area is just the product between the width and the length, so to get the area of the pool with the sidewalk we just take:

area = (total length)*(total width)

area = (2*W + 8ft)*(W + 8ft) = 2*W^2 + 3*W*8ft + 64ft^2

area = 2*W^2 + 24ft*W + 64ft^2

This is the equation that gives the total area as a function of W, the width of the pool.

If you want to learn more about rectangles, you can read:

brainly.com/question/17297081

6 0
2 years ago
Across which axis was point A reflected​
Snezhnost [94]

Answer:

When point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

Step-by-step explanation:

When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.

In other words, when point P with coordinates (x, y) is reflected across the x-axis and mapped onto point P', the coordinates of P' will be (x, -y).

Thus, the rule is:

P(x, y) → P'(x, -y)

Thus, when point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

4 0
2 years ago
HELPPP PLEASEEE!! This is due later tonight and I’m struggling! I’ve missed a few days of school from sickness! Help a girl out!
tekilochka [14]
10. 8x+4y=4. y=mx+b
-8x. -8x
4y=-8x+4
÷4. ÷4. ÷4
y = -2x +1
slope = -2. y-int= 1

11. slope is changing y over changing x
m = (y2 -y1)/(x2-x1) (0,-1) x1 = 0, y1=-1
(-4-(-1))/(-2-0) (-2,-4) x2 = -2, y2 = -4
(-4 + 1) / (-2)
-3/-2 = 3/2 answer is 3/2
12. b because negative cause it flip in x axis and it become flatter because of the fraction.
13. 2y =8-8x
÷2. ÷2 ÷2
y = 4 - 4x
Answer A
14. B
6 0
3 years ago
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