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34kurt
3 years ago
10

Determine which of the four levels of measurement​ (nominal, ordinal,​ interval, ratio) is most appropriate. ages of children: 3

comma 4 comma 5 comma 6 comma and 7ages of children: 3, 4, 5, 6, and 7 choose the correct answer below.
Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0

Answer:

The level of variable ages of children is ratio.

Explanation:

Nominal scale is the one which takes categories as its values like gender of a person.

Ordinal scale is the one which is used to show the order of values with no clear difference among them like satisfaction level of people with a service.

Interval scale is the one which shows the clear order of values with clear difference between the values with out true zero.

Ordered scale is one which not only produces the order of variables but also makes the difference between variables known along with information on the value of true zero.

Therefore, the variable which is under consideration here is the ages of children, which takes the values 3,4,5,6 and 7 is a ratio scale.


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2×3+4-5 <br>please help ​
Andru [333]

Step-by-step explanation:

PEMDAS

parentheses, exponents, multiplication, division, addition, subtraction.

first multiply:

2×3=6

6+4-5

Now add

6+4=10

Now subtract

10-5=5

5 is the answer

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3 years ago
Read 2 more answers
4/5 + 2/3 in simplest terms
RSB [31]

Answer:

\frac{8}{15}

Step-by-step explanation:

1) use this rule: \frac{a}{b} × \frac{c}{d} =\frac{ac}{bd}

\frac{4*2}{5*3}

2) simplify 4 * 2 to 8

\frac{8}{5*3}

3) simplify 5 * 3 to 15

\frac{8}{15}

8 0
2 years ago
Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 18 Pennies13 Dimes 18 Nickels1
Nezavi [6.7K]

Answer:

P(Nickel\ and\ Nickel) = 0.08091

Step-by-step explanation:

Given

Pennies = 18

Dimes = 13

Nickels = 18

Quarters = 13

Required

Probability of selecting 2 nickels without replacement

This can be represented as: P(Nickel\ and\ Nickel)

The solution is as follows

P(Nickel\ and\ Nickel) = \frac{Nickel}{Total}*\frac{Nickel-1}{Total-1}

The second nickel is reduced by 1 because the first nickel was not replaced and this also reduces the total by 1

So, we have:

P(Nickel\ and\ Nickel) = \frac{18}{62}*\frac{18-1}{62-1}

P(Nickel\ and\ Nickel) = \frac{18}{62}*\frac{17}{61}

P(Nickel\ and\ Nickel) = \frac{18*17}{62*61}

P(Nickel\ and\ Nickel) = \frac{306}{3782}

P(Nickel\ and\ Nickel) = 0.08091

6 0
3 years ago
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