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ella [17]
3 years ago
9

1 1/8+42/3. COMMON DENOMENATOR???

Mathematics
2 answers:
bearhunter [10]3 years ago
6 0

Answer:

a common denominator would be 21 bc 8 x 3 = 21

Step-by-step explanation:


Oliga [24]3 years ago
6 0
The command denominator would be 24 because 8•3=24
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1. An airline knows that only about 75% of those who make a reservation actually buy a ticket. At this rate, how many reservatio
madam [21]
We have to use proportion to solve this problem.
75% -------------------180
100% ---------------------x
crossmultiply
75*x=100*180
75x=18000           /:75
x=240 - its the answer

We have similar problem here
8%---------------------60$
100% ------------------x
crossmultiply now
8*x=60*100
8x=600        /:8
x=75 - its the answer

3 0
3 years ago
a car has 15 gallons of gas in its tank the car travels 35 miles per gallon of gas how much gas does the car used to go 100 mile
Artist 52 [7]

Answer:why are you not yeeting

Step-by-step explanation:

6 0
3 years ago
Shane and abha earned a team budget that required their team to collect no less than 2000 cans for recycling. Abha collected 178
TiliK225 [7]

Answer:

s ≥ 911

Step-by-step explanation:

Let

s = number of cans Shane could collect

Abha collected 178 more cans than Shane did.

Abha = s + 178

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling

Number of cans collected by Shane + number of cans collected by Abha ≥ 2000

s + 178 + s ≥ 2000

2s + 178 ≥ 2000

2s ≥ 2000 - 178

2s ≥ 1,822

Divide both sides by 2

s ≥ 1,822 / 2

s ≥ 911

8 0
3 years ago
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
iVinArrow [24]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

8 0
3 years ago
Sam has
Nana76 [90]

Answer: 72

Step-by-step explanation: 8x9=72

6 0
3 years ago
Read 2 more answers
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