What is the average rate of change of the function f(x)=4(2)^x from x = 0 to x = 2? Enter your answer in the box.

Mathematics

2 answers:

bekas [8.4K]3 years ago

3 0

average rate of change is just the slope from (0,f(0)) to (2,f(2))

basically, average rate of change=slope= $\frac{f(2)-f(0)}{2-0}$

evalaute each

f(2)=4(2)^2=4(4)=16

f(0)=4(2)^0=4(1)=4

so average rate of change= $\frac{16-4}{2-0}=\fracc{12}{2}=6$

average rate of change is 6

ycow [4]3 years ago

3 0

6 Just took the test. X)

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