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Katen [24]
2 years ago
10

Solve the system linear equations, using Gaussian Elimination

Mathematics
1 answer:
otez555 [7]2 years ago
5 0
Just look it up on the web that will help a lot
You might be interested in
L need help with this​
soldi70 [24.7K]

Answer:

$24.11

Step-by-step explanation:

Let the cost of the present be c.

Then (3/4)c = $18.33.

To isolate (solve for) c, mult. both sides of this equation by (4/3):

(4/3)(3/4)c = (4/3)($18.33), or

             c  =  $24.11

5 0
3 years ago
The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?
adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)

\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t  \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}

$$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$$

3 0
2 years ago
If your bike 8 miles south and then 6 miles east, what is the distance you are from your starting point?
Lady bird [3.3K]

Answer:

<em>14 miles</em>

Step-by-step explanation:

It's still 14 miles no matter which way you go.

8 0
3 years ago
Running times for 400 meters are Normally distributed for young men between 18 and 30 years of age with a mean of 93 seconds and
Luda [366]

Answer:

C. 45 and 141 seconds

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 93 seconds

Standard deviation = 16 seconds

99.7% of running times are approximately between:

By the Empirical rule, within 3 standard deviations of the mean, so between 3 standard deviations below the mean and 3 standard deviations above the mean

3 stnadard deviations below the mean

93 - 3*16 = 45 seconds

3 standard deviations above the mean

93 + 3*16 = 141 seconds

The correct answer is:

C. 45 and 141 seconds

3 0
3 years ago
Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.
Solnce55 [7]

Answer:

7 digits can be used for each position

There are a total of 5 positions

N = 7^5 = 16,807 numbers

You have 7 choices for the first position, second position, etc.

7 0
3 years ago
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