A*2 + b* = c*2
(9)*2 + (8)*2
81+64= 145
145=c*2
12.04=c
Answer:
The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
Step-by-step explanation:
In a random sample of 300 boards the number of boards that fall outside the specification is 12.
Compute the sample proportion of boards that fall outside the specification in this sample as follows:

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

The critical value of <em>z</em> for 95% confidence level is,

*Use a <em>z</em>-table.
Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
3.0 NOT SURE IF ITS CORRECT
Answer:

Step-by-step explanation:
The equation to solve is:

To get rid of the "square", we need to take square root of both sides:

Then we use algebra to find the value(s) of x. Remember, when we take square root, we have to add up a "+-" (on the right side). Shown below:

So these are 2 answers for x.
<em>Greetings from Brasil...</em>
According to the annex, we note that
1 qt = 1 quart = 0.95L
To solve this problem, just apply some rules of 3.....
1st - how many qt's are in 15.5 cups
qt cup
1 ---------- 4
X ---------- 15.5
4 · X = 1 · 15.5
4X = 15.5
X = 15.5 ÷ 4
X = 3.875qt
Last rule of 3 to know how many liters there are in 3.875qt:
qt litres
1 ---------- 0.95
3.875 ---------- Y
1 · Y = 0.95 · 3.875
<h2>Y = 3.68L</h2>
In a day a young man should drink 3.68L of water