(3n-10p)^2
=(3n-10p)(3n-10p)
=9n^2-10p-10p+100p^2
=9n^2-20p+100p^2
well, let's keep in mind that the SAS postulate, so if one Side and the Angle next to it and the following Side after the angle are equal on both triangles, both triangles are congruent. Now, we have the angle 30° with sides and 9 and 2x and sides 9 and x + 4, well, the 9's are equal, dohh, you know, if only the 2x = x + 4, we'd be golden
The answer for this is 3(k+6)^2 u need to factor this so use magic X
Answer:
The answer in the procedure
Step-by-step explanation:
we know that
The rule of the reflection of a point over the y-axis is equal to
A(x,y) ----->A'(-x,y)
That means -----> The x-coordinate of the image is equal to the x-coordinate of the pre-image multiplied by -1 and the y-coordinate of both points (pre-image and image) is the same
so
A(3,-1) ------> A'(-3,-1)
The distance from A to the y-axis is equal to the distance from A' to the y-axis (is equidistant)
therefore
To reflect a point over the y-axis
Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis
