All categories

2 years ago

HELPPPP!!!!!!!!! Please

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

3 0

Answer:

it's c

Step-by-step explanation:

don't know how to explain but pls trust me :)

You might be interested in

True or false: equilateral triangles can be classified as acute right or obtuse

Ne4ueva [31]

False, since all sides are equal all angles must be equal and when you have an obtuse or right triangle only on angle is obtuse or right. since one is different it cannot be equal on all sides making this statement false

8 0

2 years ago

The average of 10 numbers is -5. A new number is added to the list making the average -6. What is the new number?

Shtirlitz [24]

Answer:

- 16

Step-by-step explanation:

Average is calculated as

average = $\frac{total}{count}$

Thus for the given 10 numbers we have

$\frac{total}{10}$ = - 5 ( multiply both sides by 10 )

total = - 50

let the number added be x, then

$\frac{total+x}{11}$ = - 6 ( multiply both sides by 11 )

total + x = - 66, that is

- 50 + x = - 66 ( add 50 to both sides )

x = - 16

The new number is - 16

4 0

3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

2 years ago

How do I find the scale of the dilation A(3,4),A’(9,12)

Pavlova-9 [17]

Since A (3,4) A’(9,12)
You can see 3*3=9
Therefor it was enlarged by 3times
Scale factor of 3

3 0

3 years ago

Which expression is equivalent to

noname [10]

Answer:

3/5 m^2 n^3

Step-by-step explanation:

√225 = 15

√625 = 25

√m^4 = m^2

√n^6 = n^3

Put it all together and you get 15/25 m^2 n^3

Simplify 15/25 to 3/5

4 0

3 years ago

Read 2 more answers