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o-na [289]
3 years ago
7

HELPPPP!!!!!!!!! Please

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

Answer:

it's c

Step-by-step explanation:

don't know how to explain but pls trust me :)

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Which shows the equation below written in standard form ax^2+bx+c=0? x^2+6x+8=3
Charra [1.4K]

Answer:

x² + 6x + 5 = 0

Step-by-step explanation:

Given

x² + 6x + 8 = 3 ( subtract 3 from both sides )

x² + 6x + 5 = 0 ← in standard form

7 0
3 years ago
A set of data already has the values 11, 14, 23, and 16. What value would have to be added to the set for the mean of the
ad-work [718]
Your answer is 26.

We have to go at this kind of backward.

We find the average by adding up the numbers, then dividing by how many numbers we have.

In this example, we will have 5 numbers...so
x divided by 5 = 18

x/5 = 18
x = 90

The sum of all 5 numbers is 90, so then subtract the 4 numbers you already know to find the one you’re missing. (We’ll call it n)

90 - 8 - 12 - 18 - 26 = n

90 - 64 = n
n = 26

Please let me know if you have any questions.

6 0
3 years ago
6) On a trip to his grandparents, Donny drove 60 miles per hour for 45 minutes and 50 miles per hour for 30 minutes. How many mi
just olya [345]
60 miles an hour for 45 minutes = 45 miles
50 miles per hour for 30 minutes = 25 miles

Total =70 miles
7 0
3 years ago
Read 2 more answers
Write an algebraic expression for each of the statements below.
4vir4ik [10]

Answer:

i) 3x + 7

ii) x/3 = 9

iii) y = 2x +4

iv) y = 6x

5 0
2 years ago
A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50% of this population prefers t
ehidna [41]

Answer:

The probability that more than a third of the buyers would prefer brown is 0.8491.

Step-by-step explanation:

This is binomial problem with n=15 and p=0.50.

The binomial formula of probaility is:

P(X=x)=\frac{n!}{x!(n-x)!} p^{x} (1-p)^{n-x}

More than a third of the buyers: 15÷3=5

We have to find P(x>5).

P(x>5) = 1 - P(x≤5) = 1 - P(x=0) - P(x=1) - P(x=2) - P(x=3) - P(x=4) - P(x=5)

P(x=0)=\frac{15!}{0!15!} (0.5)^{0} (1-0.5)^{15}=0.00003

P(x=1)=\frac{15!}{1!14!} (0.5)^{1} (1-0.5)^{14}=0.00046

P(x=2)=\frac{15!}{2!13!} (0.5)^{2} (1-0.5)^{13}=0.00320

P(x=3)=\frac{15!}{3!12!} (0.5)^{3} (1-0.5)^{12}=0.01389

P(x=4)=\frac{15!}{4!11!} (0.5)^{4} (1-0.5)^{11}=0.04165

P(x=5)=\frac{15!}{5!10!} (0.5)^{5} (1-0.5)^{10}=0.09164

P(x>5) = 1 - P(x≤5)= 1- 0.00003 - 0.00046 - 0.00320 - 0.01389 - 0.04165 - 0.09164 = 0.8491

4 0
3 years ago
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