All categories

3 years ago

Wendy purchased 9 pizzas for x dollars. She spent a total of $85.50. Find the value of x

Mathematics

2 answers:

disa [49]3 years ago

5 0

X=9.5 all you do is divide the total by the other factor you have

Paul [167]3 years ago

5 0

Answer: 9.5

Step-by-step explanation: the first thing you do is you do 85.50 divide it by 9 and you get 9.5. if you want to make sure that is correct answer do 9.5 times 9 and you'll get 85.50

You might be interested in

I cant figure out 17 :3 and 68 :12 are equivalent

sleet_krkn [62]

Answer:

17:3 is 68:12 simplified

15 slices will be eaten in 10 minutes

Step-by-step explanation:

first off 17:3 is 68:12 simplified (both 68 and 12 go into 4 resulting in 17 and 3)

you have to divide 10 by 2 which will give you 5

and then multiply by 3

to get 15

5 0

3 years ago

Read 2 more answers

3x-2y=-6 how to find the slope,y-intercept,and x-intercept

wolverine [178]

You have to move your variables around.<span />

7 0

3 years ago

5x+2y=10; (-2, 9) if -2 is x and 9 is y

Dovator [93]

What are you looking for. slope?

4 0

3 years ago

What is 9,150,000,000,000,000,000

Anettt [7]

<span>9.15E18 --- how we learn to write it</span>

6 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago