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Evgesh-ka [11]
3 years ago
7

The Lewis structures of both pyridine and pyrrole have an electron pair on the nitrogen atom, suggesting that both substances mi

ght possess basic properties. However, only pyridine reacts readily with HCl to form pyridinium chloride, while pyrrole is rather unreactive. Explain clearly, using relevant diagrams to illustrate/clarify your answer.

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
3 0

Explanation:

Lone pairs are present on nitrogen atoms of both pyridine and pyrrole.

In pyrrole, the electron pair on nitrogen is involved in resonance and hence does not available for bonding. Therefore, pyrrole does not possess basic character and remains unreactive towards HCl.

In case of pyridine, as 6 pi electrons are present in the ring, so, electron pair of nitrogen does not participate in resonance. So, because of presence of lone pair, pyridine possess basic character and hence, reacts readily reacts with HCl.

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Where are the most reactive nonmetal elements found on the periodic table?
Varvara68 [4.7K]

Answer is: group 17 on the periodic table.

Group 17 (halogens) elements are: fluorine (F), chlorine (Cl), bromine (Br) and iodine (I).

They are very reactive and easily form many compounds.  

Fluorine and chlorine are in gaseous state, bromine is liquid and iodine is in solid state in room temperature.

Halogens need to gain one electron to have electron cofiguration like next to it noble gas.

For example, fluorine has 9 electrons and it gain easily one electron in chemical reaction to have electron configuration like noble gas neon (Ne) with 10 electrons.  

6 0
3 years ago
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Good and bad effects of changes in materials in the environment​
Sholpan [36]

Answer:

Composting, recycling, technological development, water cycle and photosynthesis are changes that have good effects. Some changes have bad effect like pollution and destruction of habitat and lose of lives.

Explanation:

hope it helps

8 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.71 g of ethane is
DanielleElmas [232]

Answer:

6g

Explanation:

Step 1:

The balanced equation for the reaction between gaseous ethane and gaseous oxygen. This is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Step 2:

Determination of the masses of C2H6 and O2 that reacted and the mass of CO2 produced from the balanced equation. This is illustrated below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

Mass of C2H6 from the balanced equation = 2 x 30 = 60g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 7 x 32 = 224g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 4 x 44 = 176g

From the balanced equation above,

60g of C2H6 reacted with 224g of O2 to produce 176g of CO2.

Step 3:

Determination of the limiting reactant.

We need to determine the limiting reactant as it will be needed to obtain the maximum mass of CO2.

From the balanced equation above,

60g of C2H6 reacted with 224g of O2.

Therefore, 2.71g of C2H6 will react with = (2.71 x 224)/60 = 10.12g of O2.

From the above calculation, we can see that a higher mass of O2 is needed to react with 2.71g of C2H6, therefore, O2 is the limiting reactant.

Step 4:

Determination of the maximum mass of CO2 produced when 2.71 g of ethane is mixed with 7.6 g of oxygen.

The limiting reactant is used to determine the maximum mass.

From the balanced equation above,

224g of O2 produce 176g of CO2.

Therefore, 7.6g of O2 will produce = (7.6 x 176)/224 = 5.97g ≈ 6g of CO2

From the calculations made above, the maximum mass of CO2 produced is 5.97 ≈ 6g

5 0
4 years ago
1. The chemical formula for sodium bromide iş NaB. *<br> True<br> False
zheka24 [161]
The answer is False for sodium bromide it would be NaBr
3 0
3 years ago
Five different substances are given to you to be dissolved in water. Which substances are most likely to undergo dissolution in
9966 [12]

Answer:

NaF and KBr

Explanation:

These two substances contain pure ionic bonds. LiI is a covalent compound because of the Large polarizing power of Li and the high polarizability of I(Fajan's rules). The other compounds mentioned are organic compounds. They are not soluble in water at all.

7 0
4 years ago
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