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4 years ago

In a oxidation–reduction reaction, oxidation and reduction must occur simultaneously. Is this statement true or false?

Chemistry

1 answer:

bogdanovich [222]4 years ago

5 0

Answer:

True

Explanation:

Oxidation and reduction always occur simultaneously. Gave example when a substance is oxidized or reduced? 1) The substance gaining oxygen or losing electron is oxidized. 2) The substance losing oxygen ( or gaining electron) is reduced. hope this helps you :)

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Do you have any ideas for a sodium poster project other than a salt shaker?

vovangra [49]

Answer:

- chips n other food items (ones with salt)

- clorox

- aleve

- baking soda

5 0

3 years ago

How to balance _h2s+ _o2 = _h2o+ _s

goldfiish [28.3K]

Answer:

2H₂S + 1O₂ → 2H₂O + 2S

Explanation:

SOLUTION :-

Balance it by using 'hit & trial' method , and you'll get the answer :-

2H₂S + 1O₂ → 2H₂O + 2S

VERIFICATION :-

In reactant side of equation :-

Number of atoms in H = 2×2 = 4
Number of atoms in S = 2×1 = 2
Number of atoms in O = 1×2 = 2

In product side of equation :-

Number of atoms in H = 2×2 = 4
Number of atoms in O = 2×1 = 2
Number of atoms in S = 2×1 = 2

Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.

5 0

3 years ago

PLEASE MATCH AND LABEL THEM A TO E ILL CASHAPP YOU MONEY.

Aloiza [94]

41) c

42) e

43) b

44) d

45) a

7 0

3 years ago

What mass of carbon monooxide must be burned to produce 175 kJ of heat under standard state condaitions?

Sphinxa [80]

Answer:

17.3124 grams

Explanation:

Given;

Amount of heat to be produced = 175 kJ

Molar mass of the carbon monoxide = 12 + 16 = 28 grams

Now,

The standard molar enthalpy of carbon monoxide = 283 kJ/mol

Thus,

To produce 175 kJ heat, number of moles of CO required will be

= Amount heat to be produced / standard molar enthalpy of CO

= 175 / 283

= 0.6183

Also,

number of moles = Mass / Molar mass

therefore,

0.6183 = Mass / 28

Mass of the CO required = 0.6183 × 28 = 17.3124 grams

7 0

4 years ago

A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by?

AURORKA [14]

A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by ventilation.

The two following principles determine the type of ventilation: Considering the impact of the contaminant's vapour density and either positive or negative pressure is applied.

Consider a vertical tank that is filled with methane gas. Methane would leak out if we opened the top hatch since its vapour density is far lower than that of air. A second opening could be built at the bottom to greatly increase the process' efficiency.

A faster atmospheric turnover would follow from air being pulled in via the bottom while the methane was vented out the top. The rate of natural ventilation will increase with the difference in vapour density. Numerous gases that require ventilation are either present in fairly low concentrations or have vapor densities close to one.

3 0

2 years ago