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Anna007 [38]
3 years ago
13

Five different substances are given to you to be dissolved in water. Which substances are most likely to undergo dissolution in

water?lithium iodide, LiIsodium fluoride, NaFpotassium bromide, KBrbenzene, C6H6hexane, C6H14
Chemistry
1 answer:
9966 [12]3 years ago
7 0

Answer:

NaF and KBr

Explanation:

These two substances contain pure ionic bonds. LiI is a covalent compound because of the Large polarizing power of Li and the high polarizability of I(Fajan's rules). The other compounds mentioned are organic compounds. They are not soluble in water at all.

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The mass of a proton is 1.00728 amu andthat of a neutron is 1.00867 amu. What is the binding energy pernucleon (in J) of a Co nu
andreyandreev [35.5K]

Answer:

The binding energy per nucleon = 1.368*10^-12  (option D)

Explanation:

<u>Step 1:</u> Data given

The mass of a proton is 1.00728 amu

The mass of a neutron is 1.00867 amu

The mass of a cobalt-60 nucleus is59.9338 amu

Step 2: Calculate binding energy

The mass defect = the difference between the mass of a nucleus and the total mass of its constituent particles.

Cobalt60 has 27 protons and 33 neutrons.

The mass of 27 protons = 27*1.00728 u = 27.19656 u

The mass of 33 neutrons = 33*1.00867 u = 33.28611 u

Total mass of protons + neutrons = 27.19656 u + 33.28611 u = 60.48267 u

Mass of a cobalt60 nucleus = 59.9338 amu

Mass defect = Δm = 0.54887 u

ΔE =c²*Δm

ΔE = (3.00 *10^8 m/s)² *(0.54887 amu))*(1.00 g/ 6.02 *10^23 amu)*(1kg/1000g)

Step 3: Calculate binding energy per nucleon

ΔE = 8.21 * 10^-11 J

8.21* 10^-11 J / 59.9338 = 1.368 *10^-12

The binding energy per nucleon = 1.368*10^-12  (option D)

3 0
3 years ago
The element californium (cf) sells for $1000 per µg. assuming 6.02 x 1023 atoms of cf have a mass of 251 grams, how many atoms o
saveliy_v [14]

Answer:- 2.40*10^1^0atoms

Solution:- It is a simple unit conversion problem. We could solve this using dimensional analysis.

We know that, 1 US dollar = 100 cents

1 cent  = 1 US penny

So, 1 US dollar = 100 US pennies

1g=10^6\mu g

Let's make the set up starting with 1 penny as:

1penny(\frac{$1}{100pennies})(\frac{1\mu g}{$1000})(\frac{1g}{10^6\mu g})(\frac{6.02*10^2^3atoms}{251g})

= 2.40*10^1^0atoms

Therefore, we can bye 2.40*10^1^0atoms of Cf in one US penny.

3 0
3 years ago
2503(g) → 2502(g) O2(g)
Verizon [17]

Answer:

7.146

Explanation:

use the equilibrium equation

6 0
3 years ago
4AI+30 2 &gt; 2AI2O3 What id the chemical reaction?
vesna_86 [32]
This is a combination reaction.  Look at the 2 elements on left and a compound on the right.
7 0
3 years ago
Calculate the molarity of each of the following solutions. Use the periodic table if necessary.
-Dominant- [34]

Answer: 2.8

Explanation: just took the quiz

8 0
2 years ago
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