Tom want to buy a sweater for $30.in which city will it be the most expensive

A rectangular sheet of paper is folded diagonally from A to C what is the length of side B

sveta [45]

Answer:

AC = $\sqrt{AB^2 + BC^2}$

Step-by-step explanation:

Here we have to draw the figure.

When the rectangle is folded A to C. we get a right triangle.

Here we have to use the Pythagorean theorem to find the side lenght of B.

The sides length of B is AC.

By the Pythagorean theorem, the sum of the squares of the sides is equal to the square of the hypotenuse.

Therefore,

AC^2 = AB^2 + BC^2

Taking the square roots on both sides, we get

AC = $\sqrt{AB^2 + BC^2}$

7 0

3 years ago

Use the inverse of this function to select the correct graph.

xxTIMURxx [149]

Answer:

D

Step-by-step explanation: (i know this part. its the graph im a tiny bit unsure about)

x __ y

2 __2

3 __ 2.387

7__ 3

3 0

3 years ago

Use the scatter plot of car resale values to answer the following question.

Nataly_w [17]

Answer:

A

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The time between arrivals of taxis at a busy intersection is exponentially distributed with a mean of 10 minutes. (a) What is th

Sindrei [870]

Answer:

a) 0.0025

b) 0.9975

c) 23.03 minutes

d) 23.03 minutes

Step-by-step explanation:

Let X be the random variable that measures the time waited for a taxi.

If X is exponentially distributed with a mean of 10 minutes,then the probability that you have to wait more than t minutes is

$\large P(X>t) = e^{-t/10}$

a)

1 hour = 60 minutes, so the probability that you wait longer than one hour is

$\large P(X>60)=e^{-6}=0.0025$

b)

Due to the “memorylessness” of the exponential distribution, the probability that you have to wait 10 or less minutes after you have already waited for one hour, is the same as the probability that you have to wait 10 or less minutes

$\large P(X\leq 10)=1-e^{-6}=0.9975$

c)

We want x so that

P(X>x)=0.1

$\large e^{-x/10}=0.1\rightarrow -x/10=ln(0.1)\rightarrow x=-10ln(0.1)=23.03\;minutes$

d)

We want P(X<x)=0.9

$\large 1-e^{-x/10}=0.9\rightarrow e^{-x/10}=0.1\rightarrow x=-10ln(0.1)=23.03\;minutes$

4 0

3 years ago

Is a measure of 26 inches "far away" from a mean of 16 inches? As someone with knowledge of statistics, you answer "it depen

alexandr402 [8]

Answer: Hello!

In a normal distribution, between the mean and the mean plus the standar deviation, there is a 34.1% of the data set, between the mean plus the standar deviation, and the mean between two times the standard deviation, there is a 16.2% of the data set, and so on.

If our mean is 16 inches, and the measure is 26 inches, then the difference is 10 inches between them.

a) if the standar deviation is 2 inches, then you are 10/2 = 5 standar deviations from the mean.

b) yes, is really far away from the mean, in a normal distribution a displacement of 5 standar deviations has a very small probability.

c) Now the standar deviation is 7, so now 26 is in the range between 1 standar deviation and 2 standar deviations away from the mean.

Then this you have a 16% of the data, then in this case, 26 inches is not far away from the mean.

3 0

2 years ago