(i) The area of the cross section ABCDEFG is 1771.6cm³
(ii) The volume of the concrete lab is 212592 cm³
(iii) the total surface area of the concrete slab is 30284 cm²
(iv) The mass of the concrete slab is 40746.8 kg/m³.
Given, dimensions are 120 cm by 60 cm by
40 cm.
(i) area of cross section = 40 × 60 ₋ π(60 ₋10 ₋ 10)/2 . 1/2
= 1771.6 cm³
(ii) the volume of the concrete slab = 40 × 60 × 120 ₋ 1/2 π((60 ₋ 10 ₋10)/2)² . 120
= 212592 cm³
(iii) The total surface area is:
=40 × 120 × 2 ₊ 60 × 120 ₊ 1771.6 × 2 ₊ 10 × 120 × 2 ₊ 1/2 π(60 ₋ 10 ₋10) × 120
= 30284 cm²
(iv) Mass of the concrete slab given density is 2300 kg/m³
Mass = Volume × density
Mass = 17.716 m³ × 2300
= 40746.8 kg/m³
Hence we get the mass as 40746.8 kg/m³.
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Answer:
b
Step-by-step explanation:
The translation of the question given is
A line that passes through the points A (2,1) and B (6,3) and another line passes through A and through the point (0, y). What is y worth, if both lines are perpendicular?
Answer:
y = 5
Step-by-step explanation:
Line 1 that passes through A (2,1) and B (6,3)
Slope (m1) = 3-1/6-2 = 2/4 = 1/2
y - 1 =
( x -2)
2y - 2 = x- 2
y = 
Line 2 passes through A (2,1) and (0,y)
slope (m2) =
Line 1 and Line 2 are perpendicular
m1*m2 = -1
*
= -1
y-1 = 4
y = 5
slope = -2
Equation of Line 2
Y-1 = -2(x-2)
y -1 = -2x +4
2x +y = 5