Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
Answer:
54 sq units
Step-by-step explanation:
The triangle at the top (FAB) has a base of 10 and a height of 3. Area of triangle is 1/2bh so 1/2(10 * 3) = 1/2 * 30 = 15 sq units
If you cut off the triangle you have a trapezoid, EBCD. A trapezoid is (b1 + b2)/2 * h, so (6 + 7)/2 * 6 = 13/2 * 6 = 6.5 * 6 = 39 sq units
Add them together: 15 + 39 = 54 sq units
Answer:The answer is 5 pounds of apples
Step-by-step explanation:
She had $100 and she gave $3 to her sister so $10-$3=$7 and her parent quadrupled her remaining dollars which was $7 so $7x4=$28 the answer is $28
