4x^2+25=4x^2=-25=x^2=-25/4 has no solution. because, negative number do not live under radical except complex number
Arc PR is 156 degrees. Since both angles are are making the forming arc they should be congruent. You can put (5x+23)=(9x-21) which is x=11.
Then you plug in 11 into your equation; 5(11)+23=78.
Since the vertex is on the outside of the circle then the arc is forms is 2 times the value of the angle.
78(2)=156
You have an equation and a table with the x value given.
Replace x in the formula with the x value in the table and solve for y.
y = x^2 + 1
y = (-3)^2 + 1 = 9+1 = 10
y = (-2)^2 +1 = 4+1 = 5
y = (-1)^2 +1 = 1+1 = 2
y = (0)^2 + 1 = 0+1 = 1
y = (1)^2 +1 = 1+1 = 2
y = (2)^2 +1 = 4+1 = 5
y = (3)^2 +1 = 9+1 = 10
First, you make 9 into a fraction which would become 36/4
then, subtract 9/4 from both sides so that would give you 3/4x = 27/4
then divide each side by 3/4 (same thing as multiply by its reciprocal) and that would give you x=9
